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mamaluj [8]
3 years ago
11

*GEOMETRY QUESTION* NO LINKS & PLZ EXPLAIN!!!

Mathematics
1 answer:
ololo11 [35]3 years ago
8 0

in my view I think the 3rd one

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siniylev [52]
1 is the answer!! Hope this helps
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3 years ago
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17 POINTS! I will also give Brainliest!
Karo-lina-s [1.5K]

Answer:

c 39

Step-by-step explanation:

Parameter is the sum of the lengths of all sides of a polygon. The sides of the polygon are PT, TS, SR, RQ, and QP. To get the length of a side, we use the distance formula: Each vertex in the polygon has its corresponding points:\

So to get the length of side PT, we use the distance formula and the vertices of side PT:

The length of PT is

The same procedure is done for the other 4 sides and the following are the answers:

And by adding all the sides, you get the perimeter:

By rounding off, the answer is 39 units.

have a nice day

3 0
3 years ago
The length of a rectangle is 5 inches more than its vedth. The area of the rectangle is equal to
jarptica [38.1K]

Answer:

  • The width = x = 14
  • The length = x+5 = 14+5 = 19

Step-by-step explanation:

Let  l  = length,  w = width,  A = area =  l×w , and  P  = perimeter =  2(l+w)

Let 'x' be the width

As the length 'l' of a rectangle is 5 inches more than its width.

so the length will be = x+5

As the Area of the rectangle is equal to  2 inches more than 4 times the perimeter.

A = 4P + 2

so the equation becomes

l × w = 4×2(l+w)+2

substituting w=x, l = x+5,

(x+5)x = 8(x+5+x)+2

x²+5x = 8(5+2x)+2

x²+5x = 40+16x+2

x²+5x = 16x+42

x²+5x-16x-42 =0

x²-11x-42=0

x^2-11x=42

\mathrm{Add\:}a^2=\left(-\frac{11}{2}\right)^2\mathrm{\:to\:both\:sides}

x^2-11x+\left(-\frac{11}{2}\right)^2=42+\left(-\frac{11}{2}\right)^2

x^2-11x+\left(-\frac{11}{2}\right)^2=\frac{289}{4}

\left(x-\frac{11}{2}\right)^2=\frac{289}{4}

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solving

x-\frac{11}{2}=\sqrt{\frac{289}{4}}

x-\frac{11}{2}=\frac{\sqrt{289}}{\sqrt{4}}

x-\frac{11}{2}=\frac{\sqrt{289}}{2}

x-\frac{11}{2}=\frac{17}{2}

x-\frac{11}{2}+\frac{11}{2}=\frac{17}{2}+\frac{11}{2}

x=14

similarly solving

x-\frac{11}{2}=-\sqrt{\frac{289}{4}}

x-\frac{11}{2}=-\frac{17}{2}

x-\frac{11}{2}+\frac{11}{2}=-\frac{17}{2}+\frac{11}{2}

x=-3

so

x = 14, or x = -3

As the width 'x' can not be negative.

so x = 14

Thus,

  • The width = x = 14
  • The length = x+5 = 14+5 = 19

6 0
3 years ago
Find the area of each figure. round to the nearest tenth if necessary
zhuklara [117]

Answer:

120

Step-by-step explanation:

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The sum of 423 and 65 is
Akimi4 [234]

Answer:

488

Step-by-step explanation:

8 0
3 years ago
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