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ser-zykov [4K]
2 years ago
9

Which graph represents the solution to this system of inequalities?

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
7 0

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The solution region is above the line with positive slope, and below the line with negative slope. It will be in the left quadrant of the X made by the crossing lines. The line with positive slope is steeper.

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7nadin3 [17]

Answer:

F

Step-by-step explanation:

7 0
3 years ago
Can someone help me
erik [133]

Answer:

   6 < x < 23.206

Step-by-step explanation:

To properly answer this question, we need to make the assumption that angle DAC is non-negative and that angle BCA is acute.

The maximum value of the angle DAC can be shown to occur when points B, C, and D are on a circle centered at A*. When that is the case, the sine of half of angle DAC is equal to 16/22 times the sine of half of angle BAC. That is, ...

  (2x -12)/2 = arcsin(16/22×sin(24°))

  x ≈ 23.206°

Of course, the minimum value of angle DAC is 0°, so the minimum value of x is ...

  2x -12 = 0

  x -6 = 0 . . . . . divide by 2

  x = 6 . . . . . . . add 6

Then the range of values of x will be ...

  6 < x < 23.206

_____

* One way to do this is to make use of the law of cosines:

  22² = AB² + AC² -2·AB·AC·cos(48°)

  16² = AD² + AC² -2·AD·AC·cos(2x-12)

The trick is to maximize x while satisfying the constraints that all of the lengths are positive. This will happen when AB=AC=AD, in which case the equations be come ...

  22² = 2·AB²·(1-cos(48°))

  16² = 2·AB²·(1 -cos(2x-12))

The value of AB drops out of the ratio of these equations, and the result for x is as above.

4 0
3 years ago
Read 2 more answers
Which can be a next step in the construction of an angle with a side on line l that is congruent to ∠ABC?
iren2701 [21]
A) use a straightedge to draw a line thought D and F
6 0
3 years ago
Find the missing sum of a triangle
melamori03 [73]

Answer:

where you supposed to add a picture or..?

Step-by-step explanation:

3 0
3 years ago
Which is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)?
Annette [7]
(4,5),(-3,-1)
slope = (-1 - 5) / (-3 - 4) = -6/-7 = 6/7

y - y1 = m(x - x1)
slope(m) = 6/7
using points (-3,-1)...x1 = -3 and y1 = -1
now we sub...pay attention to ur signs
y - (-1) = 6/7(x - (-3) =
y + 1 = 6/7(x + 3) <===
6 0
3 years ago
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