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2 years ago

Which graph represents the solution to this system of inequalities?

Mathematics

1 answer:

zhannawk [14.2K]2 years ago

7 0

9514 1404 393

Answer:

see attached

Step-by-step explanation:

The solution region is above the line with positive slope, and below the line with negative slope. It will be in the left quadrant of the X made by the crossing lines. The line with positive slope is steeper.

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Please help i got a f on it and i am redoing it i will give 28 points for the right answer

Savatey [412]

Answer:

11/16

Step-by-step explanation:

12 divided by (2+2/3)^2 =1.6875

1.6875 in a decimal form is 11/16

5 0

2 years ago

Read 2 more answers

Determine the following:

dolphi86 [110]

Answer:

a) P(X = 0) = 0.5997

b) P(X = 9) = 0.0016

c) P(X = 8) = 0.0047

d) P(X = 5) = 0.4018

Step-by-step explanation:

These following problem are examples of the binomial probability distribution.

Binomial probability

Th binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

(a) for n = 4 and π = 0.12, what is P(X = 0)?

$P(X = 0) = C_{4,0}.(0.12)^{0}.(0.88)^{4} = 0.5997$

(b) for n = 10 and π = 0.40, what is P(X = 9)?

$P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016$

(c) for n = 10 and π = 0.50, what is P(X = 8)?

$P(X = 8) = C_{10,8}.(0.5)^{8}.(0.5)^{2} = 0.0047$

(d) for n = 6 and π = 0.83, what is P(X = 5)?

$P(X = 5) = C_{6,5}.(0.83)^{5}.(0.17)^{1} = 0.4018$

3 0

2 years ago

helpp Points (0, −3) and (7, 11) lie on the same line in the standard xy-coordinate plane. What is the slope of this line? A. -3

Kamila [148]

Answer: D

Step-by-step explanation: m is slope. m = (11+3)/(7-0). m = 14/7 or 2. It is D

6 0

2 years ago

PLZZZ HELP FAST WILL GIVE BRAINLYEST!!!!!!!!!!!

morpeh [17]

Answer:

Changing the net force on an object can either impress on it even more force in the direction that it is moving, making it go faster, or if you apply more net force on the object against it, then it decreases acceleration

Step-by-step explanation:

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2 years ago

Three forces act on a hook. Determine the magnitude of the resultant of the force.

Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

$\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y$

$\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y$

$\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y$

The resultant force is the sum of these vectors,

$\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y$

and has magnitude

$|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N$

The closest answer is D.

5 0

2 years ago