2 years ago

What is the minimum for Z=2x+5y

Mathematics

1 answer:

DENIUS [597]2 years ago

3 0

Answer:

there is no minimum or maximum for this equation

Step-by-step explanation:

Hope this helps

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Mrs. Steward needs to save (4.2 X 10^6) dollars for her children's college education. If she can save (1.4 X 10^2) each month, h

qwelly [4]

Answer: 30,000 months or 2,500 years

She'd better start saving more haha.

Step-by-step explanation:

$Goal=4.2x10^6\\Savings/month=1.4x10^2$

$\frac{4.2x10^6}{1.4x10^2} =(\frac{4.2}{1.4})x10^(^6^-^2^)=(3)x10^4=3x10^4 =30000 months=\frac{30000}{12}=2500years$

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3 years ago

At a carnival, it costs $0.30 for each chance to throw a ring over a bottle to win a prize. If Anita and Jerome get an even amou

spin [16.1K]

Answer:

c - amount of chances

Step-by-step explanation:

0.30c + 0.30c = 3.60

0.60c = 3.60

c = 6

They will get 6 throws each.

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3 years ago

Show the steps to solve the system of equation. x-2y+3z=-4 , 3x+y-z=0 , 2x+3y-5z=1

Taya2010 [7]

Answer:

x= -1, y = 6, z = 3

Step-by-step explanation:

let me solve it with Gaussian Elimination

8 0

3 years ago

What's 0.003 is 1/10 of what?

zvonat [6]

0.03 you just times it by ten or if its a decimal take away the 0 infront of it

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3 years ago

If y=(x^2-4)^5(3x+4)^4

alexira [117]

Answer:

$y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)$

Step-by-step explanation:

$y=(x^2-4)^5(3x+4)^4$

$y'=[\frac{d}{dx}(x^2-4)^5](3x+4)^4+(x^2-4)^5[\frac{d}{dx}(3x+4)^4]$

$y'=10x(x^2-4)^4(3x+4)^4+(x^2-4)^5(12(3x+4)^3)$

$y'=10x(x^2-4)^4(3x+4)^4+12(x^2-4)^5(3x+4)^3$

$y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)$

5 0

2 years ago