Solve x^2-6x+25 = 0 by completing the square.
1 answer:
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Based on the docx you showed me, the equation for the parabola is 
and you want a table of values for a linear equation that intersects the parabola at (5, 6) and (-2, 34).
If you use these two points to create a line we get the equation:
(I just used point slope form)
This can be simplified to:
Now we just need to create a table of points on this line. We already have the points you gave and we can also use the y-intercept:
and the x-intercept: 
.
So our table of value can be:
x | y
______|________
-2 | 34
0 | 242 / 7
5 | 6
121/20 | 0
If you use these two points to create a line we get the equation:
This can be simplified to:
Now we just need to create a table of points on this line. We already have the points you gave and we can also use the y-intercept:
So our table of value can be:
x | y
______|________
-2 | 34
0 | 242 / 7
5 | 6
121/20 | 0
I didn’t know which problem you specifically needed help with, but I hope this helps.
Answer:
Graph One.
Step-by-step explanation:
See below. The graph is in a straight line, also known as linear. The other graphs are not. Also, if you look at the range (y) of the tables, you can see the increase is linear as it is increasing by .5 (1/2) everytime.
