f(x)=lnx
y=f(x)
dy/dx= 1/x
tangent at (x,y) has slope 1/x
eqn of tangent is y = mx + c
since the tangent passes through origin, c=0
substitute y = lnx and m= 1/x to above eqn
lnx = 1
x=e
y=lne=1
Answer:
x = 4y/3
Step-by-step explanation:
y = 3x/4
Multiply both sides by 4.
4y = 3x
Divide both sides by 3.
x = 4y/3
Answer: I believe the correct answer is option D.
Answer: The last 3 choices
I think it’s the first one
