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2 years ago

8. If the perimeter of a square is 62 centimeters, what is its area?

Mathematics

2 answers:

Katen [24]2 years ago

7 0

240.25 centimeters^2

andreyandreev [35.5K]2 years ago

5 0

Step-by-step explanation:

Perimeter= 62 cm

4 × side = 62

side = 62/4

=15.5 cm

Area = (side)²

= (15.5)²

=240.25 cm²

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Step-by-step explanation:

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3 years ago

Two bonds are available on the market as follows: Bond 1: Face value $250, 5 years to maturity at a (simple) interest rate of 5%

tester [92]

The value of r is 5.95%

Step-by-step explanation:

The formula of the simple interest is I = P r t, where

P is the initial amount of money
r is the interest rate in decimal
t is the time

Bond 1:

∵ The face value is $250

∴ P = 250

∵ The value is in the bond for 5 years

∴ t = 5

∵ The simple interest rate is 5%

∴ r = 5% = 5 ÷ 100 = 0.05

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∴ The interest of Bond 1 is $62.5

Bond 2:

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∴ P = 350

∵ The value is in the bond for 3 years

∴ t = 3

∵ The simple interest rate is r

∵ I = P r t

- Substitute the values of P and t in the rule

∴ I = (350)(r)(3) = 1050 r

∴ The interest of Bond 2 is 1050 r

∵ The both bonds yield the same interest to maturity

- Equate the interests of bonds 1 and 2

∵ 1050 r = 62.5

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- Multiply it by 100% to change it to percentage

∵ r = 0.0595 × 100% = 5.95%

∴ r = 5.95%

The value of r is 5.95%

Learn more:

You can learn more about interest in brainly.com/question/11149751

#LearnwithBrainly

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3 years ago

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The equation is Y= 4x +3

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3 years ago

Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

Given equation:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

To complete the square for a hyperbola

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$

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2 years ago

8. If the perimeter of a square is 62 centimeters, what is its area?​

8. If the perimeter of a square is 62 centimeters, what is its area?