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2 years ago

What is 9 + 10? (You have to say the right thing)

Mathematics

2 answers:

Andru [333]2 years ago

8 0

Answer:

9+10=19

have a nice day..

nexus9112 [7]2 years ago

3 0

Answer:

Step-by-step explanation:

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Marta has 1 cubic yard of sand to build a wall in the shape of a rectangular prism that is 20 inches tall and 5 inches wide. To

DanielleElmas [232]

Answer:

466,56 inches

Step-by-step explanation:

1 yard = 36 inches

1 cubic yard = 36*36*36 = 46656 cubic inches

46656 = 20*5*l => l = 46656/100 = 466, 56 inches

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4 years ago

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Nata [24]

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A. C. E.

Step-by-step explanation:

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3 years ago

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|c-10|=3 absolute value

Norma-Jean [14]

The final solutions are C1=7, C2=14

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3 years ago

Integrate e^x(sin(x) cos(x))

Karo-lina-s [1.5K]

$I=\int e^x(\sin(x)\cos(x))dx=\int e^x(\frac{1}{2}\sin(2x))dx=\frac{1}{2}\int e^x\sin(2x)dx$

$\text{If }u=\sin(2x)\to du=2\cos(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
\text{Using }\int u\,dv=uv-\int v\,du:\\\\
I=\frac{1}{2}(e^x\sin(2x)-\int e^x(2\cos(2x))dx)\\\\
2I=e^x\sin(2x)-2\underbrace{\int e^x\cos(2x)dx}_{I_2}$

Looking for $I_2$ :

$\text{If}~u=\cos(2x)\to du=-2\sin(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
I_2=e^x\cos(2x)-\int e^x(-2\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(2\sin(x)\cos(x))dx\\\\ I_2=e^x\cos(2x)+4\int e^x(\sin(x)\cos(x))dx=e^x\cos(2x)+4I$

Replacing:

$2I=e^x\sin(2x)-2I_2\iff\\\\2I=e^x\sin(2x)-2(e^x\cos(2x)+4I)\iff\\\\
2I=e^x\sin(2x)-2e^x\cos(2x)-8I\iff\\\\
10I=e^x\sin(2x)-2e^x\cos(2x)\iff\\\\
I=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))\\\\
\boxed{\int e^x(\sin(x)\cos(x))dx=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))+C}$

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3 years ago

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ki77a [65]

Answer:

3321

Step-by-step explanation:

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2 years ago