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Soloha48 [4]
2 years ago
15

Mr. Carlson suffers from allergies. When allergy season arrives, his doctor recommends that he take 1200 mg of his medication th

e first day, and decrease the dosage by one fourth each day for one week. How much medication will he take on day 6?​
Mathematics
1 answer:
Firdavs [7]2 years ago
5 0

Answer:

Hope this helps!!

Step-by-step explanation:

1200 x .25 = 300/ 1200 -300 = 900

900 x .25 = 225/ 900 - 225= 675

675 x .25 = 168.75/ 675 - 168.75= 431.25

431.25 x .25 = 107.8125/ 431.25 - 107.8125 = 323.4375

323.4375 x .25 = 80.859 / 323.4375 - 80.859 =242.758

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Which zero pair could be added to the function f(x)=x^2+12x+6 so that the function can be written in vertex form?
andrew11 [14]
<span>f(x) = x</span>² <span>+ 12x + 6  </span>→ y = x² + 12x + 6<span>

Let us convert the standard form into vertex form.

1) Complete the squares. Isolate x</span>² and x terms.
<span>y - 6 = x</span>² + 12x
<span>
2) Create the perfect square trinomial. Whatever number is added on one side must also be added on the other side. 

y - 6 + 36 = x</span>² + 12x + 36<span>
y + 30 = (x + 6)</span>²
<span>y = (x + 6)</span>² - 30  ← Vertex form
<span>
To check:

y = (x + 6) (x + 6) - 30
y = x</span>² + 6x + 6x + 36 - 30
<span>y = x</span>² + 12x + 6<span>

The zero that could be added to the given function is 36, -36</span>
4 0
3 years ago
(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13
jolli1 [7]

Answer:

y(x)=3e^{5x}-2xe^{5x}

Step-by-step explanation:

The given differential equation is y''-10y'+25y=0

The characteristics equation is given by

r^2-10r+25=0

Finding the values of r

r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5

We got a repeated roots. Hence, the solution of the differential equation is given by

y(x)=c_1e^{5x}+c_2xe^{5x}...(i)

On differentiating, we get

y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)

Apply the initial condition y (0)= 3 in equation (i)

3=c_1e^{0}+0\\\\c_1=3

Now, apply the initial condition y' (0)= 13 in equation (ii)

13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2

Therefore, the solution of the differential equation is

y(x)=3e^{5x}-2xe^{5x}

5 0
3 years ago
Whats -20x 50????????????
Leokris [45]

Answer:

-1,000

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How do you graph x-y=1 and 3x+2y=-12
Nataliya [291]

Answer:

Graph the equations

Step-by-step explanation:

x - y = 1

3x + 2y = - 12

Rewrite equations into y=mx+b form:

y = -1 + x

y = -6 - 1.5x

Graph it!

3 0
2 years ago
Find the missing value ​
lapo4ka [179]

Answer:

-10

Step-by-step explanation:

since the answer is positive, we need a negative number, if we use -10,two negatives makes a positive, so it becomes

-8 +10=2

4 0
3 years ago
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