Given the reaction: 2 hi h2 + i2. if kc' for the reverse reaction is 1.85 x 10-2 at 425°c, what is kc for the forward reaction a
1 answer:
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The concentration of [H3O+] will be 6.3 x M
Mathematically, pH = -log [H+] or -log [H3O+]
With a pH of 13.2:
-log [H3O+] = 13.2
log [H3O+] = -13.2
[H3O+] = 6.3 x M
More on pH can be found here: brainly.com/question/491373
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Answer : The pH of the solution is, 2.67
Explanation :
The equilibrium chemical reaction is:
Initial conc. 0.450 0 0
At eqm. (0.450-x) x x
As we are given:
The expression for equilibrium constant is:
Now put all the given values in this expression, we get:
The concentration of = x = 0.00212 M
Now we have to calculate the pH of solution.
Therefore, the pH of the solution is, 2.67