<h3>
Answer:</h3>
0.125 mol Ca
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
5.00 g Ca
<u>Step 2: Identify Conversions</u>
Molar mass of Ca - 40.08 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.12475 mol Ca ≈ 0.125 mol Ca
#8 would be radiation
Because of the heat it produces for the air in the home
#9 Conduction
Because it’s preventing physical heat transfer
#10 convection
Because it is stopping the air from rising
#11 Radiation
Because the heat is emitting from the stove and warms him, but not by direct contact
#12 Conduction
Because the heat transfers from the top of the stove to the cats fur.
#13 Conduction
Because the stove under it heats it through contact
#14 I think Radiation
Because the heat warms up the dish through the air in the oven
#15 Radiation
Because the heat is emitting from the fire.
#16 Conduction
Because the blanket is warming you through physical contact.
I’m not completely sure but the is the best I got. Good luck!
4 moles as their raport is 4/2 or 2/1
The effect of an insoluble impurity, such as sand, on the observed melting point of a compound would be none. It will not depress or elevate the melting point of the compound. Instead, it would affect the reading if you are trying to determine the melting point of the compound. This is because you might be missing the actual melting point of the compound since you will be waiting for the whole sample to liquify. You would not be able to determine exactly that temperature because of the insoluble impurity would have a different melting point than that of the compound.
