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MrRissso [65]
3 years ago
12

Which substance do plants use to capture light energy from the sun? a) Carbon dioxide b) Chlorophyll c) Glucose d) Oxygen

Chemistry
2 answers:
PolarNik [594]3 years ago
8 0

Answer:

I don't know the answer to this either

Explanation:

sorry:(

Akimi4 [234]3 years ago
6 0

Answer: chlorophyll

Explanation:

The substance that plants use to capture light energy from the sun is referred to as chlorophyll.

The chlorophyll is a colored pigment that is used by the plants for photosynthesis. The function of the chlorophyll is that it absorbs the energy from the sun which is then turned into a chemical energy.

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A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling
aniked [119]

<u>Answer:</u> The mass of glucose in final solution is 0.420 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}        .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated glucose solution

M_2\text{ and }V_2 are the molarity and volume of diluted glucose solution

We are given:

M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL

Putting values in above equation, we get:

0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g

Hence, the mass of glucose in final solution is 0.420 grams

3 0
3 years ago
Two hydrogen atoms covalently bond to form a hydrogen molecule.
ankoles [38]

Answer:

B

Explanation:

the energy of two separate hydrogen atoms decreases as they approach each other, and the single electrons on each atom are shared to form a covalent bond.

7 0
3 years ago
Which ion has the smallest radius?<br> (1) O2-<br> (2) S2-<br> (3) Se2-<br> (4) Te2-
podryga [215]

Answer:


                  Option-1 (O²⁻) is the correct answer.


Explanation:

                       All given anions contains same charge. So, we can ignore the effect of charge on these anions.


As we know all given compounds belongs to same group (Group 6) in periodic table. And from top to bottom along the group the elements are placed as,


                                                          Oxygen O


                                                          Sulfur S


                                                          Selenium Se


                                                          Tellurium Te


Hence, moving from top to bottom along the group the number of shells increases. And with increase in number of shell the atomic or ionic radii increases. As Oxygen is present at the top of the group, therefore, it has the smallest radius due to less number of shells.

5 0
3 years ago
Read 2 more answers
50 ml of 0.2 M acetic acid is shaken with 10 g activated charcoal. The concentration of acetic acid is reduced to 0.5 times the
Olegator [25]

Answer:

0.03 g_{acid}/g_{charcoal}

Explanation:

The amount adsorbed (solute) is the acetic acid, and the adsorbent is the activated charcoal. The mass of the adsorbent is 10 g.

So, we need to calculate the mass of the acetic acid as follows:

m = n*M = C*V*M

Where:

n: is the number of moles = C*V

M: is the molecular mass =  60.052 g/mol

C: is the final concentration of the acid = 0.5*0.2 mol/L = 0.10 mol/L

V: is the volume = 50 ml = 0.050 L

m_{acid} = C*V*M = 0.10 mol/L*0.050 L*60.052 g/mol = 0.30 g

Now, the amount of solute adsorbed per gram of the adsorbent is:

\frac{m_{acid}}{m_{charcoal}} = \frac{0.30 g}{10 g} = 0.03 g_{acid}/g_{charcoal}

Therefore, the amount of solute adsorbed per gram of the adsorbent is 0.03 g/g.

I hope it helps you!

3 0
3 years ago
How much mass would a nucleus that is composed of 15 protons and 18 neutrons have?
Olin [163]
The mass is the total number of protons and neutrons there are in the nucleus. There are 15 and 18 neutrons, that means the mass is 33
15 + 18 = 33
5 0
4 years ago
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