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Sergeu [11.5K]
3 years ago
8

Ascorbic acid, or vitamin C (C6H8O6, molar mass = 176 g/mol), is a naturally occurring organic compound with antioxidant propert

ies. A healthy adult’s daily requirement of vitamin C is 70-90 mg. A sweet lime contains 2.87×10−4 molof ascorbic acid.
To determine whether the ascorbic acid in a sweet lime meets the daily requirement, calculate the mass of ascorbic acid in 2.87×10−4 mol of ascorbic acid.
Chemistry
1 answer:
ki77a [65]3 years ago
7 0

Answer:

The mass of ascorbic acid in 2.87×10−4 mol are 50,5 mg

Explanation:

Molar mass = 176 g/mol

Moles . molar mass = grams.

2,87 x10*-4 m . 176 g/m = 50,5 x10*-3 grams

A human can take one sweet lime and half to cover the daily requirement of vitamin C. =)

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What type of nuclear decay is shown by the reaction below?
pantera1 [17]

Answer:

B. Alpha

Explanation:

Alpha decays always split into an element and He.

Beta decays always split into an element and e- (eletrons).

Gamma decays always split into an element and radiation.

3 0
3 years ago
SO
Burka [1]

Answer:

\large \boxed{\text{E) 721 K; B) 86.7 g}}

Explanation:

Question 7.

We can use the Combined Gas Laws to solve this question.

a) Data

p₁ = 1.88 atm; p₂ = 2.50 atm

V₁ = 285 mL;  V₂ = 435 mL

T₁ = 355 K;     T₂ = ?

b) Calculation

\begin{array}{rcl}\dfrac{p_{1}V_{1}}{T_{1}}& =&\dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{1.88\times285}{355} &= &\dfrac{2.50\times 435}{T_{2}}\\\\1.509& = &\dfrac{1088}{T_{2}}\\\\1.509T_{2} & = & 1088\\T_{2} & = & \dfrac{1088}{1.509}\\\\ & = & \textbf{721K}\\\end{array}\\\text{The gas must be heated to $\large \boxed{\textbf{721 K}}$}

Question 8. I

We can use the Ideal Gas Law to solve this question.

pV = nRT

n = m/M

pV = (m/M)RT = mRT/M

a) Data:

p = 4.58 atm

V = 13.0 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 385 K

M = 46.01 g/mol

(b) Calculation

\begin{array}{rcl}pV & = & \dfrac{mRT}{M}\\\\4.58 \times 13.0 & = & \dfrac{m\times 0.08206\times 385}{46.01}\\\\59.54 & = & 0.6867m\\m & = & \dfrac{59.54}{0.6867 }\\\\ & = & \textbf{86.7 g}\\\end{array}\\\text{The mass of NO$_{2}$ is $\large \boxed{\textbf{86.7 g}}$}

7 0
3 years ago
Carbon monoxide (CO) is a poisonous gas because it binds very strongly to the oxygen carrier hemoglobin in blood. A concentratio
velikii [3]

<u>Answer:</u> The amount of CO that is occupied in the room is 1.98\times 10^3L

<u>Explanation:</u>

We are given:

Concentration of CO = 8.00\times 10^2ppm=800pm by volume

This means that 800\mu L\text{ or }800\times 10^{-6} of CO is present in 1 L of blood

To calculate the volume of cuboid, we use the equation:

V=lbh

where,

V = volume of cuboid

l = length of cuboid = 10.99 m

b = breadth of cuboid = 18.97 m

h = height of cuboid = 11.89 m

V=10.99\times 18.97\times 11.89=2478.83m^3

Converting this into liters, by using conversion factor:

1m^3=1000L

So,  2478.83m^3=2.479\times 10^6L

Applying unitary method:

In 1 L of blood, the amount of CO present is 800\times 10^{-6}

So, in 2.479\times 10^6L of blood, the amount of CO present will be = \frac{800\times 10^{-6}}{1}\times 2.479\times 10^{6}=1983.2L=1.98\times 10^3L

Hence, the amount of CO that is occupied in the room is 1.98\times 10^3L

8 0
3 years ago
On a summer day, you take a road trip through Death Valley, California, in an antique car. You start out at a temperature of 21°
MrRissso [65]
<span>There is only one formula to use and we should assume ideal gas. This equation is: PV=nRT. For the following questions manipulate this equation to get the answer.
 1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol
 2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa
 3. Since the answer in #2 is more than 269 kPa, then the tires will likely burst. 4. Reduce pressure way below the limit 269 kPa.</span>
4 0
3 years ago
While conducting a lab experiment, Ali calculated that 1.20 E6 Joules of heat were needed to melt 18.5 kilograms of an unknown s
nordsb [41]

Answer:

Latent heat of fusion of the substance is 6.49\times 10^{4}J/kg

Explanation:

Latent heat of fusion denotes amount of energy (heat) per unit mass required to melt a solid material at constant temperature and pressure i.e. at it's melting point

Here amount of heat required = 1.20\times 10^{6}J

Mass of unknown substance being melted = 18.5 kg

So, latent heat of fusion of the substance = (required heat energy to melt)/(mass of the unknown substance) = \frac{1.20\times 10^{6}}{18.5}J/kg=6.49\times 10^{4}J/kg

So, latent heat of fusion of the substance is 6.49\times 10^{4}J/kg

7 0
3 years ago
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