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3 years ago

How does the energy provided by the Sun affect global ocean currents?

Chemistry

1 answer:

777dan777 [17]3 years ago

8 0

The answer is C. The sun heats waters near the equator, which then move toward the polls where the waters cool.

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Which energy transformation is represented in the diagram?

Paha777 [63]

A nuclear to thermal and radiant

Explanation:

Nuclear fission is the disintegration of the force that holds the nucleus of the atom together, creating two different but lighter nuclei.

In nuclear fission, it seeks to break the force of attraction or nuclear force that joins the protons and neutrons that form the nucleus of an atom. Neutrons without electric charge are used against the nucleus of the atom to produce enough excitation energy to deform the nucleus into two halves.

6 0

3 years ago

Read 2 more answers

2.7g of aluminum metal is placed into solution hydrochloric acid to form aluminum chloride and hydrogen gas.

Sidana [21]

Explanation:

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2 years ago

Solid NaI is slowly added to a solution that is 0.0079 M Cu+ and 0.0087 M Ag+.Which compound will begin to precipitate first?NaI

NeTakaya

Answer :

AgI should precipitate first.

The concentration of $Ag^+$ when CuI just begins to precipitate is, $6.64\times 10^{-7}M$

Percent of $Ag^+$ remains is, 0.0076 %

Explanation :

$K_{sp}$ for CuI is $1\times 10^{-12}$

$K_{sp}$ for AgI is $8.3\times 10^{-17}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgI has a smaller than CuI then AgI should precipitate first.

Now we have to calculate the concentration of iodide ion.

The solubility equilibrium reaction will be:

$CuI\rightleftharpoons Cu^++I^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Cu^+][I^-]$

$1\times 10^{-12}=0.0079\times [I^-]$

$[I^-]=1.25\times 10^{-10}M$

Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

$AgI\rightleftharpoons Ag^++I^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ag^+][I^-]$

$8.3\times 10^{-17}=[Ag^+]\times 1.25\times 10^{-10}M$

$[Ag^+]=6.64\times 10^{-7}M$

Now we have to calculate the percent of $Ag^+$ remains in solution at this point.

Percent of $Ag^+$ remains = $\frac{6.64\times 10^{-7}}{0.0087}\times 100$

Percent of $Ag^+$ remains = 0.0076 %

8 0

4 years ago

8. 00 g of ethane gas, c2h6, is burned in oxygen. What volume of carbon dioxide gas is produced at 1. 00 atm and 25. 0°c?.

Sonbull [250]

Answer:

Explanation:1 g CH

T = 350 K, P = 1 atm

PV=nRT=

w×R×T

1×V=

×0.0821×350

V=0.495 L

V=495cm

8 0

2 years ago

Which ligand binds tightest? ligand A, with a dissociation constant ( Kd ) of 10−9 M ligand D, with a percent occupancy of 80% a

Delvig [45]

Answer:

The answer will be Ligand A with a dissociation constant (Kd) of $10^{-9}$ M

Explanation:

When the dissociation constant in the ligand is small (in order of nano) ( $10^{-9}$ ) it will be more tied. Due to a dissociation constant measures how much a ligand can be able to be separated from the protein so if the number is small it means that the ligand is highly binded to the protein.

On the other hand, the occupancy percentage of the ligand does not imply binding. Conversely, a High-affinity ligand binding with the proteins implies that a relatively low concentration of a ligand is adequate to occupy the maximum ligand-binding site.

6 0

3 years ago