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solniwko [45]
3 years ago
14

What are the Golgi body and Endoplasmic Reticulum both responsible for in the cell?

Chemistry
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer:

B the golgi body and rough/smooth endoplasmic reticulum are able to synthesise vesicles the only difference is that one synthesises vesicles that go from one organelle to another where as the other synthesises vesicles that travel to the outside of the cell.

Explanation:

You might be interested in
When water is heated in an ocean the liquid water changes from and turns into?
sasho [114]
Hello!

The answer is Evaporation

When you add heat to water, it boils, releasing gas into the air. This is called Evaporation. The water changes from a liquid to a gas.

Hope this helped!
6 0
3 years ago
A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal
bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}

\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}

Solving for V₂ , we get:

<u>V₂ = 45.0 L</u>

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0
4 years ago
3. Fill in: Name the organelle or organelles that perform each of the following functions.
Mekhanik [1.2K]

A. Chloroplasts

B. The cell wall and the vacuole

C. Vacuoles

D. The mitochondrion

8 0
3 years ago
CH,(g) + 20,(g) - CO2(g) + 2H20() + S90.4 kJ<br> What is the type of reaction that is occurring?
7nadin3 [17]

Answer:

The type of reaction that is occuring is 164.8 kJ.

3 0
3 years ago
What is the temperature of 0.5 moles of water vapor that occupies 120 dm3 and applies a pressure of 15,000 Pa to its container?
MArishka [77]
Use the ideal gas law:

PV = nRT

so, T = PV / nR

n=0.5
V= 120 dm^3 = 120 L  (1 dm^3 = 1 L)
R = 1/12
P = 15,000 Pa =  0.147 atm     (1 pa = 9.86 10^{-6} )

Put the values:

T = PV / nR
T = (0.147) (120) / (0.5) (1/12)
T= 426 K
6 0
3 years ago
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