Answer:
(a) The volume of water in the quarry is 6.496 x 10⁷ m³.
(b) The total mass of mercury is 1.19 x 10⁻³ kg.
Explanation:
(a) The volume of water can be calculated like:
Volume = depth x surface
In order to have coherence between units we will use proportions to transform km² to m².
![2.887km^{2} .\frac{(10^{3}m)^{2} }{(1km)^{2} } =2.887 \times 10^{6} m^{2}](https://tex.z-dn.net/?f=2.887km%5E%7B2%7D%20.%5Cfrac%7B%2810%5E%7B3%7Dm%29%5E%7B2%7D%20%7D%7B%281km%29%5E%7B2%7D%20%7D%20%3D2.887%20%5Ctimes%2010%5E%7B6%7D%20m%5E%7B2%7D)
Then,
Volume = 22.50 m x 2.887 x 10⁶ m² = 6.496 x 10⁷ m³
(b) We can find out the total mass of mercury using proportions. We will need these relations:
1 L = 10⁻³ m³
1 pg = 10⁻¹² g
1 kg = 10³ g
![6.496\times10^{7} m^{3} (H_{2}O).\frac{1L(H_{2}O)}{10^{-3}m^{3}(H_{2}O) } .\frac{18.3pg(Hg)}{1L(H_{2}O)} .\frac{10^{-12}g(Hg) }{1pg(Hg)} .\frac{1kg(Hg)}{10^{3}g(Hg) } =1.19\times 10^{-3} kg(Hg)](https://tex.z-dn.net/?f=6.496%5Ctimes10%5E%7B7%7D%20m%5E%7B3%7D%20%28H_%7B2%7DO%29.%5Cfrac%7B1L%28H_%7B2%7DO%29%7D%7B10%5E%7B-3%7Dm%5E%7B3%7D%28H_%7B2%7DO%29%20%20%7D%20.%5Cfrac%7B18.3pg%28Hg%29%7D%7B1L%28H_%7B2%7DO%29%7D%20.%5Cfrac%7B10%5E%7B-12%7Dg%28Hg%29%20%7D%7B1pg%28Hg%29%7D%20.%5Cfrac%7B1kg%28Hg%29%7D%7B10%5E%7B3%7Dg%28Hg%29%20%7D%20%3D1.19%5Ctimes%2010%5E%7B-3%7D%20kg%28Hg%29)
They are saying that every theory can eventually be changed a bit due to further research. It does not mean the theory is bad, just that it can become better.
Answer:
The answer to your question is: letter B.
Explanation:
Carbon atom double-bonded to an oxygen atom C= O,
a) Carbohydrate group this group does not exist
b)Carbonyl group This option is right, carbonyl group is C=O
c) Hydroxyl group This option is incorrect, hydroxyl group is OH, very different from C=O
d) Ketone group Ketone group does not exist, ketones have the same functional group as aldehydes (C=O)
The attractive forces between the neighboring particles of a substance are known as intermolecular forces. The state of a substance relies upon the strength of the intermolecular forces among the molecules in a substance.
There are three kinds of intermolecular forces, that is, the dipole-dipole forces, ion-dipole forces, and the London dispersion forces. On the basis of the kinds of intermolecular forces, it is concluded that the intermolecular forces primarily relies upon the nature of the molecule's bonding.
Thus, on the basis of the nature of bonding between the associating atoms in a molecule one can know about the nature of intermolecular forces. On the basis of Newton's law of gravitation, all the physical bodies get fascinated towards each other, and it is known that each physical body comprises of matter. Thus, the matter is fundamentally attracted by other matter.
<h3>
Answer:</h3>
0.0520 mol Zn
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.40 g Zn
<u>Step 2: Identify Conversions</u>
Molar Mass of Zn - 65.39 g/mol
<u>Step 3: Convert</u>
- Set up:
![\displaystyle 3.40 \ g \ Zn(\frac{1 \ mol \ Zn}{65.39 \ g \ Zn})](https://tex.z-dn.net/?f=%5Cdisplaystyle%203.40%20%5C%20g%20%5C%20Zn%28%5Cfrac%7B1%20%5C%20mol%20%5C%20Zn%7D%7B65.39%20%5C%20g%20%5C%20Zn%7D%29)
- Divide:
![\displaystyle 0.051996 \ mol \ Zn](https://tex.z-dn.net/?f=%5Cdisplaystyle%200.051996%20%5C%20mol%20%5C%20Zn)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.051996 mol Zn ≈ 0.0520 mol Zn