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3 years ago

What are the Golgi body and Endoplasmic Reticulum both responsible for in the cell?

Chemistry

1 answer:

jarptica [38.1K]3 years ago

6 0

Answer:

B the golgi body and rough/smooth endoplasmic reticulum are able to synthesise vesicles the only difference is that one synthesises vesicles that go from one organelle to another where as the other synthesises vesicles that travel to the outside of the cell.

Explanation:

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Describe three services that banks provide

FinnZ [79.3K]

Three services that banks provide are:

loans, credit cards, and savings accounts

Hope this helps you :)

5 0

3 years ago

Read 2 more answers

The theoretical yield of a reaction is the amount of product obtained if the limiting reactant is completely converted to produc

docker41 [41]

Answer:

The theoretical yield of NH3 produced by the reaction is 16.89 grams

Explanation:

Step 1: Data given

Mass of N2 = 13.90 grams

Molar mass of N2 = 28.0 g/mol

Mass H2 = 6.440 grams

Molar mass H2 = 2.02 g/mol

Step 2: The balanced equation

N2(g) + 3 H2(g) → 2 NH3(g)

Step 3: Calculate moles

Moles = mass / molar mass

Moles N2 = 13.90 grams / 28.0 g/mol

Moles N2 = 0.496 moles

Moles = 6.440 grams / 2.02 g/mol

Moles H2 = 3.19 moles

Step 4: Calculate limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

N2 is the limiting reactant. It will completely be consumed (0.496 moles)

H2 is in excess. There will react 3*0.496 = 1.488 moles

there will remain 3.19 - 1.488 = 1.702 moles

Step 5: Calculate moles NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 0.496 moles N2 we will have 2*0.496 = 0.992 moles NH3

Step 6: Calculate mass NH3

Mass NH3 = moles NH3 * molar mass NH3

Mass NH3 = 0.992 moles * 17.03 g/mol

Mass NH3 = 16.89 grams

The theoretical yield of NH3 produced by the reaction is 16.89 grams

4 0

3 years ago

**PLEASE HELP WITH SCIENCE**

fgiga [73]

it has an electrons in a fixed path together on energy levels.

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3 years ago

What is the name of this hydrocarbon?

vovikov84 [41]

A) 2,3-dimethylpentane

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4 years ago

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In a titration, acetic acid is used as the analyte and sodium hydroxide is the titrant. At the equivalence point, will the ph be

ValentinkaMS [17]

Titration involves acetic acid as the analyte and sodium hydroxide as the titrant. ph is more than 7 at the equivalency point.

The titration's equivalence point is the moment at which adequate titrant has been introduced to react to all of the material being titrated. A strong acid combined with something like a weak base produces a somewhat acidic salt. Similarly, combining a strong base with a mild acid yields a slightly basic salt.

When acetic acid combines with NaOH, it produces the salt sodium acetate and water. When acetic acid, CH3COOH, interacts with sodium hydroxide, sodium acetate, CH3COONa, and water are formed.

CH3COO- + H2O → CH3COOH + OH-

The acetate ion's reaction raises the ph to over 7.

Moles of acetic acid is equivalent to moles of sodium hydroxide at the equivalence point. As additional sodium hydroxide is added, the solution will become pink.