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lawyer [7]
2 years ago
7

Our day is 24 hours long because that is the time it takes the earth to

Chemistry
2 answers:
Marianna [84]2 years ago
3 0
Complete one rotation. 

Hope this helps.
Anna [14]2 years ago
3 0
Our day is 24 hours long because that is the time it takes the earth to make one rotation on it's axis.
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AveGali [126]
A plateau is a flat, elevated landform that rises sharply above the surrounding area on at least one side. Plateaus occur on every continent and take up a third of the Earths land. They are one of the four major landforms, along with mountains, plains, and hills.
7 0
3 years ago
Read 2 more answers
How are elements similar to those in the same group on the periodic table ​
enot [183]

Answer:

All the members of a group of elements have the same number of valence electrons and similar chemical properties.

Explanation:

The vertical columns on the periodic table are called groups or families because of their similar chemical behavior.

5 0
3 years ago
How does Gregor Mendel's work with pea plants affect human life today? OA A. People continue to cross pea plants to fix Mendel's
lana [24]

Answer:

B

Explanation:

Not sure, but that one makes the most since

4 0
3 years ago
14. What volume (mL) of water do I need to add to 425
Reptile [31]

Answer:

212.5 mL

both the original and the diluted solution have 0.765 moles of KCl

Explanation:

c1V1 = c2V2

V2 = c1V1/c2 = (1.8 M×425 mL)/1.2 M = 637.5 mL

(637.5 - 425) mL = 212.5 mL

n = (1.8 mol/L)(0.425 L) = 0.765 moles of KCl

since it's a dilution, the diluted solution has the same number of moles as the original solution, 0.765 moles of KCl

7 0
2 years ago
I NEED HELP PLEASE, THANKS! :)
marin [14]

Answer:

\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}

Explanation:

1. Calculate the moles of copper(II) hydroxide

\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}

2. Calculate the molecules of copper(II) hydroxide

\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}

6 0
3 years ago
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