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dedylja [7]
3 years ago
5

Anyone know the volume of this shape?

Mathematics
1 answer:
lozanna [386]3 years ago
5 0

Answer:

volume =

3.14 \times 15 \times 15 \times 5 \\  = 3532.5cm {}^{2}

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What is the sign of the product (–5)(–3)(–8)(–6)?
Likurg_2 [28]
The correct answer is B

EXPLANATION

Let us do the first product,

We have;

(-5)\times (-3)

We can re-group the sign and the numbers to obtain;

(-\times -)(5\times 3)

But we know that; negative times negative is positive. So the product becomes,

+(5\times 3)

Similarly for the second product,

We have;

(-8)\times (-6)

We can again re-group the sign and the numbers to obtain;

(-\times -)(8\times 6)

But we know that; negative times negative is positive. So the product becomes,

+(8\times 6)

Putting all together gives,

+(5\times 3) \times +(8\times 6)

Finally, positive times positive will also give positive. That is,

+(5 \times 3)(8 \times 6)
4 0
3 years ago
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Determine the angle of elevation if the slope is 0.3415
miv72 [106K]

Using the slope concept, considering it's value of 0.3415, it is found that the angle of elevation is of 18.86º.

<h3>What is a slope?</h3>

The slope is given by the vertical change divided by the horizontal change, and it's also the tangent of the angle of depression.

Hence, we have that:

\tan{\alpha} = 0.3415

\alpha = \arctan{0.3415} = 18.86^\circ

More can be learned about the slope concept at brainly.com/question/18090623

#SPJ1

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Find 2/3 of 24<br><br><br> Help ASAP plz!! Got to get finished tonight
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Please mark Brainliest
If u need an explanation lemme know
8 0
3 years ago
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O panglica a fost taiata, prin 5 taieturi , in bucati cu lungimea de 35 cm . Cati metri masura panglica?
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4 years ago
NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
3 years ago
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