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cluponka [151]
2 years ago
5

Please help ill mark brilliant​

Mathematics
2 answers:
sergejj [24]2 years ago
5 0

Answer:

<h2>2</h2>

Step-by-step explanation:

Look at the picture.

-Dominant- [34]2 years ago
3 0
Answer: 2

Explanation: :3
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What is the slope of x-4y=10-4y
gizmo_the_mogwai [7]

Answer:

0 or undefined

Step-by-step explanation:

Graph it.

Vertical lines have no slope.

7 0
4 years ago
If your monthly income is $300 and you spend $50 on clothes, what percent of your monthly budget is spent on clothing
nata0808 [166]
Here is the answer to the problem above. So, if the monthly income is $300 and $50 was spent on clothing, we will find the percentage of $50 from $300 by dividing 50 by 300 then multiply the quotient by 100. So the answer is 16.67%. So the answer is 16.67%. Hope this answers your question.
3 0
3 years ago
Read 2 more answers
Find the center of mass of the wire that lies along the curve r and has density =4(1 sin4tcos4t)
dolphi86 [110]

The mass of the wire is found to be 40π√2 units.

<h3>How to find the mass?</h3>

To calculate the mass of the wire which runs along the curve r ( t ) with the density function δ=5.

The general formula is,

Mass = \int_a^b \delta\left|r^{\prime}(t)\right| d t

To find, we must differentiate this same given curve r ( t ) with respect to t to estimate |r'(t)|.

The given integration limits in this case are a = 0, b = 2π.

Now, as per the question;

The equation of the curve is given as;

r(t) = (4cost)i + (4sint)j + 4tk

Now, differentiate this same given curve r ( t ) with respect to t.

\begin{aligned}\left|r^{\prime}(t)\right| &=\sqrt{(-4 \sin t)^2+(4 \cos t)^2+4^2} \\&=\sqrt{16 \sin ^2 t+16 \cos ^2 t+16} \\&=\sqrt{16\left(\sin t^2+\cos ^2 t\right)+16}\end{aligned}

Further simplifying;

\begin{aligned}&=\sqrt{16(1)+16} \\&=\sqrt{16+16} \\&=\sqrt{32} \\\left|r^{\prime}(t)\right| &=4 \sqrt{2}\end{aligned}

Now, use integration to find the mass of the wire;

       \begin{aligned}&=\int_a^b \delta\left|r^{\prime}(t)\right| d t \\&=\int_0^{2 \pi} 54 \sqrt{2} d t \\&=20 \sqrt{2} \int_0^{2 \pi} d t \\&=20 \sqrt{2}[t]_0^{2 \pi} \\&=20 \sqrt{2}[2 \pi-0] \\&=40 \pi \sqrt{2}\end{aligned}

Therefore, the mass of the wire is estimated as 40π√2 units.

To know more about density function, here

brainly.com/question/27846146

#SPJ4

The complete question is-

Find the mass of the wire that lies along the curve r and has density δ.

r(t) = (4cost)i + (4sint)j + 4tk, 0≤t≤2π; δ=5

5 0
2 years ago
A sample of iron ore has a density of 7.87 what is its mass? Show all of your work. If it measures 7.5 cm x 2.53 em x 7.15 cm,
mr_godi [17]

Answer:

Mass=1068gr

Step-by-step explanation:

Volume= 7.5 cm x 2.53 cm x 7.15 cm=135.7cm^3

Density=7.87gr/cm^3

Mass=Density*Volume=135.7*7.87=1068gr

7 0
3 years ago
Help help help help
Alex

Answer:

<h3>b=\frac{t-5}{4}</h3>

Step-by-step explanation:

4b+5=t

First, you must get the variable alone! Substract 5 from both sides!

4b<u>+5=t </u>

    -5  -5

The 5 cancels out because 5-5=0

The new equation is 4b=t-5

You must divide by 4 to get the variable alone since your solving for b!

<u>4b=t-5</u>

4      4

b= \frac{t-5}{4} \\

This is your answer!

5 0
3 years ago
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