How does this app work?

2 answers:

8 0

So basically on this app you ask and answer questions. For example if you need help with a homework question you can type it in or take a picture of it and submit it and others will help answer it for you. You can also answer questions to help other people and that will help you earn points. When you ask questions however it requires you have points so remember to help other people too! Once you reach a certain amount of points you level up. Hope this helps

Sergio [31]3 years ago

7 0

On this app, you can answer other people’s questions and even ask your own. You need points to ask your own though. To get points, you need to answer more questions. Each question varies on points depending on what the person has set the amount of points to be given to the person who answers. Hope this helps!!

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8x^3-22x^2-4 divided by 4x-3

MA_775_DIABLO [31]

The answer is 24 because 8 times 3 is 24

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3 years ago

Best estimate 27x1/7

FinnZ [79.3K]

27/7 or Decimal: 3.857143

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3 years ago

What is the total surface area?

Elanso [62]

Answer:

231.5in squared

Step-by-step explanation:

Both faces area formula

Rectangle: l x w

triangle: b x h / 2

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3 years ago

A. Solve the differential equation <img src="https://tex.z-dn.net/?f=y%27%3D2x%20%5Csqrt%7B1-y%5E2%7D%20" id="TexFormula1" title

kirill [66]

$y' = \frac{dy}{dx}$

seperable differential equations will have the form
$\frac{dy}{dx} = F(x) G(y)$

what you do from here is isolate all the y terms on one side and all the X terms on the other
$\frac{dy}{G(y)} = F(x) dx$
just divided G(y) to both sides and multiply dx to both sides

then integrate both sides
$\int \frac{1}{G(y)} dy = \int F(x) dx

$

once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it

In your problem,
$G(y) = \sqrt{1-y^2}

F(x) = 2x$

so all you need to integrate is
$\int \frac{1}{\sqrt{1-y^2}} dy = \int 2x dx$

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3 years ago

The triangle below is equilateral. Find the length of side x to the nearest tenth.

Gemiola [76]

Answer:

$\sqrt{\frac{15}{2} }$ or 2.738

Step-by-step explanation:

Let’s just look at the triangle on the top with the $\sqrt{10}$ on the top and x on the bottom. (Basically the top half to the equilateral triangle)

There is a small square in the bottom right corner, which indicates that this triangle is a right triangle. This means that we can use the Pythagorean Theorem: $a^{2} +b^{2} =c^{2}$

We know that \sqrt{10} is our hypotenuse, and therefore our c in our equation. Let’s say that x=a in our equation. Therefore we are left to find b. However, b is half the length of the side of the original equilateral triangle. An equilateral triangle means that all three sides are the same length. Therefore our side would also be \sqrt{10} units long. However we know that b is half of that value, so b= $\frac{1}{2}(\sqrt{10})$ or $\frac{\sqrt{10} }{2}$