Out of 120 students in exam, 2/3 of them passed. How many students passed?
now,
no of students passed = 2/3×120
= 0.66×120
=80...
therefore <em>8</em><em>0</em><em> </em><em> </em><em>students</em><em> </em><em>were</em><em> </em><em>passed</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
y = 18
Step-by-step explanation:
Since the triangles are similar, the corresponding sides are in proportion, that is
= 
, substitute values
= 
( cross- multiply )
14y = 252 ( divide both sides by 14 )
y = 18
Answer:
the numbers next to a variable is a coefficient, for instance in 2x 2 would be the coefficient.
the constants are the numbers without variables next to them, just numbers
like terms are the term that are similar like 2x and 8x or even 5 and 3
lm not exactly sure what they mean when asking for constant terms.
Answer:
92 attendees had activity cards
Step-by-step explanation:
Let x be the number of students with activity cards. Then 130-x is the number without, and the total revenue is ...
7x +10(130 -x) = 1024
7x +1300 -10x = 1024 . . . . eliminate parentheses
-3x = -276 . . . . . . . . . . . . . collect terms; subtract 1300
x = 92 . . . . . . divide by 3
92 students with activity cards attended the dance.
_____
<em>Comment on the solution</em>
Often, you will see such a problem solved using two equations. For example, they might be ...
Let 'a' represent the number with an activity card; 'w' the number without. Then ...
- a+w = 130 . . . . the total number of students
- 7a +10w = 1024 . . . . the revenue from ticket sales
The problem statement asks for the value of 'a', so you want to eliminate w from these equations. You can do that using substitution. Using the first equation to write an expression for w, you have ...
w = 130-a
and making the substitution into the second equation gives ...
7a +10(130 -a) = 1024
This should look a lot like the equation we used above. There, we skipped the extra variable and went straight to the single equation we needed to solve.
