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mihalych1998 [28]
3 years ago
8

Write the slope intercept form of the equation of the line through the given points (-1,-5) (0,3) make sure your answer is in y=

Mx+b form
Mathematics
2 answers:
Rama09 [41]3 years ago
7 0

Answer:

y=8x+3

Step-by-step explanation:

Find the slope of the line between  ( − 1 , − 5 )  and  ( 0 , 3 )  using  m = y 2 − y 1/ 2 − x 1 , which is the change of  y  over the change of  x . Which gets you the slope of 8.

Use the slope  8  and a given point  ( − 1 , − 5 )  to substitute for  x 1  and  y 1  in the point-slope form  y − y 1 = m ( x − x 1 ) , which is derived from the slope equation  m = y 2 y 1 /2 − x 1 .

y − ( − 5 ) = ( 8 ) ( x − ( − 1 ))  

Simplify the equation and keep it in point-slope form. y + 5 = 8 ⋅ ( x + 1 ) Solve for  y .

y = 8 x + 3

jarptica [38.1K]3 years ago
4 0

y=8x+3

Find the slope of the line between  ( − 1 , − 5 )  and  ( 0 , 3 )  using  m = y 2 − y 1/ 2 − x 1 , which is the change of  y  over the change of  x . Which gets you the slope of 8.

Use the slope  8  and a given point  ( − 1 , − 5 )  to substitute for  x 1  and  y 1  in the point-slope form  y − y 1 = m ( x − x 1 ) , which is derived from the slope equation  m = y 2 y 1 /2 − x 1 .

y − ( − 5 ) = ( 8 ) ( x − ( − 1 ))  

Simplify the equation and keep it in point-slope form. y + 5 = 8 ⋅ ( x + 1 ) Solve for  y .

plus i just did this

y = 8 x + 3

Read more on Brainly.com - brainly.com/question/15921212#readmore

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The manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour. (a-1) At α = .05 i
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Answer:

The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

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Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given sample size 'n' =16

Given the manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour.

mean of the Population 'μ' = 560

Mean of the sample Χ⁻ = 538

sample standard deviation' S' = 50

<em><u>Null hypothesis</u></em><em>:H₀:μ > 560</em>

<em><u>Alternative Hypothesis</u></em><em>:H₁ : :μ < 560 (left tailed test)</em>

<em>Test statistic</em>

   t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }

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|t| = |-1.76| = 1.76

<em>Degrees of freedom </em>

<em>γ = n-1 =16-1 =15</em>

t_{\frac{\alpha }{2} } = t_{\frac{0.05}{2} } =t_{0.025} =2.131

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The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

The manufacturer’s claim is greater than 560 bags per hour

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