Answer:
The center of the circle is (2/3, 0) and radius is ±6units
Step-by-step explanation:
Given the equation of a circle given as shown;
(x-2/3)²+y² = 36
To get the radius and centre of the circle, we will compare the equation with the general equation of a circle given as;
(x-a)²+(y-b)² = r² where (a, b) is the centre of the circle and r is the radius.
Comparing with the given equation,
we will see that;
a = 2/3, b = 0 and r² = 36
If r² = 36
r = ±√36
r = ±6
This shows that the center of the circle (a, b) = (2/3, 0) and radius is ±6
