All categories

3 years ago

What are the four common traits of all muscles? What is muscle tone?

1 answer:

7 0

Answer: The four common traits of all muscles are Excitability or Irritability, contractibility, extensibility, and elasticity. Muscle tone refers to the ability of muscles to be slightly contracted at all times, even when not in use.

Explanation:

You might be interested in

Which describes intolerance?

Mariulka [41]

Intolerance - not tolerant of views, beliefs, or behavior that differ from one's own.

7 0

3 years ago

Read 2 more answers

Can I name my first born child after you?

Wittaler [7]

No you may not..............................

6 0

3 years ago

Sometimes you just dont feel like being cheerful agree or disagree

xeze [42]

Agree. Its okay to not be cheerful at times. Its actually healthy to show emotions.

8 0

3 years ago

Answer this.... Why are we still here...

Andreas93 [3]

Answer:

becuase we survive evry bit were on earth ?

Explanation:

4 0

3 years ago

Read 2 more answers

Differentiate the following functions (i) x(1+x)^3

statuscvo [17]

Answer:

$\displaystyle y' = (1 + x)^2(4x + 1)$

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Functions
Function Notation
Factoring

Calculus

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Explanation:

Step 1: Define

Identify

y = x(1 + x)³

Step 2: Differentiate

Product Rule [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot \frac{d}{dx}[1 + x]$
Derivative Property [Addition/Subtraction]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot (\frac{d}{dx}[1] + \frac{d}{dx}[x])$
Basic Power Rule: $\displaystyle y' = x^{1 - 1} \cdot (1 + x)^3 + x \cdot 3(1 + x)^{3 - 1} \cdot (0 + x^{1 - 1})$
Simplify: $\displaystyle y' = (1 + x)^3 + 3x(1 + x)^2$
Factor: $\displaystyle y' = (1 + x)^2 \bigg[ (1 + x) + 3x \bigg]$
Combine like terms: $\displaystyle y' = (1 + x)^2(4x + 1)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0

3 years ago