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3 years ago

Find the distance between the two points rounding to the nearest tenth

Mathematics

1 answer:

Alika [10]3 years ago

3 0

Answer:

Step-by-step explanation:

The x difference:

8 - 1 = 7

The y difference:

-4 - -7 = 3

Distance:

7² + 3² = 58

√58 ≅ 7.62

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bezimeni [28]

Answer:

H: 4 3/4

Step-by-step explanation:

You subtract Aaron's and Siri's ages together and you get 4 3/4

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3 years ago

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The x-y is the answer can someone please explain to me how to do

guapka [62]

Answer:

Step-by-step explanation:

$\frac{\sqrt{x-y}}{\sqrt{x+y}-\sqrt{x-y}}-\frac{\sqrt{x-y}}{\sqrt{x+y}+\sqrt{x-y}}\\\\=\frac{\sqrt{x-y}*(\sqrt{x+y}+\sqrt{x-y})-(\sqrt{x-y})*(\sqrt{x+y}-\sqrt{x-y})}{(\sqrt{x+y}-\sqrt{x-y})*(\sqrt{x+y}+\sqrt{x-y})}\\\\=\frac{\sqrt{x-y}*(\sqrt{x+y}+\sqrt{x-y}-\sqrt{x+y}+\sqrt{x-y})}{(\sqrt{x+y})^2-(\sqrt{x-y)^{2}}}\\\\=\frac{\sqrt{x-y}*2\sqrt{x-y}}{x+y-x+y}\\\\=2*\frac{x-y}{2y}=\frac{x-y}{y}\\\\(\frac{\sqrt{x-y}}{\sqrt{x+y}-\sqrt{x-y}}-\frac{\sqrt{x-y}}{\sqrt{x+y}+\sqrt{x-y}})*y=\frac{x-y}{y}*y\\\\=x-y$

4 0

4 years ago

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An ellipse is centered at the origin. Find it’s equation.

MA_775_DIABLO [31]

Answer:

(x)^2 (y)^2

---------- + --------- = 1

4 3

Step-by-step explanation:

The standard equation for an ellipse is

(x-h)^2 (y-k)^2

---------- + --------- = 1

a^2 b^2

The center is at (h,k)

The vertices are at (h±a, k)

The foci are at (h±c,k )

Where c is sqrt(a^2 - b^2)

It is centered at the origin so h,k are zero

(x)^2 (y)^2

---------- + --------- = 1

a^2 b^2

The center is at (0,0)

The vertices are at (0±a, 0)

The foci are at (0±c,0 )

The vertices are (±2,0) so a =2

The foci is 1

c = sqrt(a^2 - b^2)

1 = sqrt(2^2 - b^2)

Square each side

1 = 4-b^2

Subtract 4 from each side

1-4 = -b^2

-3 = -b^2

3= b^2

Take the square root

b=sqrt(3)

(x)^2 (y)^2

---------- + --------- = 1

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4 0

3 years ago

Find the measure of each side indicated round to the nearest 10th

earnstyle [38]

Answer:

20) 30°; 21) 21,1; 22) 6,2

Step-by-step explanation:

For the first image, you have to do csc⁻¹ 2 [OR sin⁻¹ ½] because you are solving for an angle measure. When evaluated, you get 30°.

For the second image, you have to do 13sec 52° = x [OR 13\cos 52° = x]. When evaluated, you get an approximate measure of 21,1.

For the third image, you have to do 6csc 75° = x [OR 6\sin 75° = x]. When evaluated, you get an approximate measure of 6,2.

Extended information on Trigonometric Ratios

O\H = sin θ

A\H = cos θ

O\A = tan θ

H\A = sec θ

H\O = csc θ

A\O = cot θ

I am joyous to assist you anytime.

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3 years ago

10. What is the distance between (8,7) and (3,-5)?

Anarel [89]

Answer:

distance between points=13 units

Step-by-step explanation:

distance between points= $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

put $(x_1,x_2)$ =(8,7) and $(y_1,y_2)$ =(3,-5)

distance between points= $\sqrt{(3-8)^2+(-5-7)^2}$

distance between points= $\sqrt{(-5)^2+(-12)^2}$

distance between points= $\sqrt{25+144}$

distance between points= $\sqrt{169}$

distance between points=13 units answer

8 0

3 years ago