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irga5000 [103]
3 years ago
8

Please please please help. thank you.

Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0
Lets get started :)


The First question:
Diameter = 20 ft
Radius = \frac{1}{2} of 20 (diameter) = 20 ft

Area formula of a circle is
A = \pir²
    =\pi(10)²
    =100\pi ft²
    ≈ 314 ft²

The answer will be the second option

The Second question:
radius of circle = 12mm  divided into 20 sectors area

A = \pir²
   = \pi(12)²
   = 144\pi ft²

Divide into 20 equal sector areas = \frac{144 \pi }{20} = 7.2 \pi

≈ 22.6 mm²

Your answer will be the third option

The Third Question:

90°, sector area = 36\pi , Radius = ?

\frac{angle}{360} = \frac{sector}{ \pi (r)^2}
\frac{90}{360} = \frac{36 \pi }{ \pi r^2}
\pi and \pi cancels out

We can now cross multiply
360 × 36 = 90r²
12960 = 90r²

Divide by 90 on either side

\frac{12960}{90} = \frac{90r^2}{90}
144 = r²

Take squareroot 
 \sqrt{144} = x
x = 12 in

Your answer will be the third option




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yawa3891 [41]

Answer:

cost of one medium drink = $3.80

cost of one large popcorn = $6.25

Step-by-step explanation:

Let D = cost of one medium drink

Let P = cost of one large popcorn

If a couple bought 2 medium drinks and a large popcorn for $13.85:

⇒ 2D + P = 13.85

If a family bought 3 medium drinks and 2 large popcorn for a total of $23.90:

⇒ 3D + 2P = 23.90

Rewrite 2D + P = 13.85 to make P the subject:

⇒ P = 13.85 - 2D

Substitute into 3D + 2P = 23.90 and solve for D:

⇒ 3D + 2(13.85 - 2D) = 23.90

⇒ 3D + 27.7 - 4D = 23.90

⇒ D = 3.8

Substitute found value of D into P = 13.85 - 2D to find P:

⇒ P = 13.85 - (2 x 3.8) = 6.25

Therefore,

cost of one medium drink = $3.80

cost of one large popcorn = $6.25

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My brother is in 6th grade and needs help with his math. I tried to help but I can't find any answers on it.
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Answer:

Question 1) 17.4

Question 2) 1.7

Question 3) 2.8

Question 4) 8.6

Step-by-step explanation:

Mean absolute deviation is the average distance between the data points from the set to the mean point of the data set. It shows the variability in data or how much the data points are spread.

method to calculate Mean absolute deviation:

a. calculate mean

b. calculate absolute deviation of each data point

c. add all the deviations

d. divide absolute deviation by number of points

mean absolute deviation = ∑lx_{i}-xl / n

The given problem has four sub-parts

Solution 1:

Mean= (78+99+90+80+55+56+102+88+60+42)/10

            =  750/10

            =  75

Mean absolute deviation= ( I 78-75 I + I 99-75 I+I 90-75 I + I 80-75 I +

                                             I 55-75 I + I 56-75 I + I 102-75 I + I 88- 75 I +

                                             I 60-75 I + I 42-75 I) /10

         =  (174)/10

        =  17.4

Solution 2:

Mean = (10+13+7+12+9+8+12+10+11+13)/10

              =  (105)/10

              = 10.5

Mean absolute deviation = ( I 10-10.5 I + I 13-10.5 I + I 7-10.5 I + I 12-10.5 I +

                                              I 9-10.5 I + I 8-10.5 I + I 12-10.5 I + I 10-10.5 I +

                                               I 11-10.5 I + I 3-10.5 I) /10

       =   17/10

       = 1.7

Solution 3:

Mean= (1+7+10+5+3+3+6+12+9+4)/10

            =  60/10

            =  6

Mean absolute deviation  = ( I 1-6 I + I 7-6 I + I 10-6 I + I 5-6 I + I 3-6 I +

                                               I 3-6 I + I 6-6 I + I 12- 6 I + I 9-6 I + I 4-6 I) /10

         = (28)/10

        =  2.8

Solution 4:

Mean= (30+46+25+45+18+25+15+32+40+24)/10

            =  300/10

            =  30

Mean absolute deviation  = ( I 30-30 I + I 46-30 I + I 25-30 I + I 45-30 I +

                                               I 18-30 I + I 25-30 I + I 15-30 I + I 32-30 I +

                                               I 40-30 I + I 24-30 I) /10

         = (86)/10

        =  8.6

!

8 0
3 years ago
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