The areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)
<h3>How to determine the total areas?</h3>
<u>The figure 1</u>
In this figure, we have
Length = x + 1
Width = 4
The area is calculated as:
Area = Length * Width
So, we have
Area = 4(x + 1)
<u>The figure 2</u>
In this figure, we have
Length = d + 4
Width = 7
The area is calculated as:
Area = Length * Width
So, we have
Area = 7(d + 4)
<u>The figure 3</u>
In this figure, we have
Length = y + 3
Width = y
The area is calculated as:
Area = Length * Width
So, we have
Area = y(y + 3)
Hence, the areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)
Read more about areas at:
brainly.com/question/24487155
#SPJ1
Based on the 5 trials, 1 carton of eggs is expected to contain at least one broken egg, on average
<h3>How to determine the number of cartons</h3>
From the question, we understand that only one of the first 10 double-digit numbers is between 01 and 08
This means that:
The average carton or the expected value of eggs in the simulation is 1
Hence, 1 carton of eggs is expected to contain at least one broken egg, on average
Read more about expected values at:
brainly.com/question/15858152
The equation of the parabolas given will be found as follows:
a] general form of the parabolas is:
y=k(ax^2+bx+c)
taking to points form the first graph say (2,-2) (3,2), thus
y=k(x-2)(x-3)
y=k(x^2-5x+6)
taking another point (-1,5)
5=k((-1)^2-5(-1)+6)
5=k(1+5+6)
5=12k
k=5/12
thus the equation will be:
y=5/12(x^2-5x+6)
b] Using the vertex form of the quadratic equations:
y=a(x-h)^2+k
where (h,k) is the vertex
from the graph, the vertex is hence: (-2,1)
thus the equation will be:
y=a(x+2)^2+1
taking the point say (0,3) and solving for a
3=a(0+2)^2+1
3=4a+1
a=1/2
hence the equation will be:
y=1/2(x+2)^2+1
Answer:
6/54 or 1/9
Step-by-step explanation:
6/54 reduces to 1/9
hope this helps
