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vovangra [49]
3 years ago
9

What is an equation of the line that passes through the points (-2, -5) and (-1, 1)?

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
8 0

Answer: y=6x+7

Step-by-step explanation:

To find the equation of the line, we want to find the slope with the formula m=\frac{y_2-y_1}{x_2-x_1}.

m=\frac{1-(-5)}{-1-(-2)} =\frac{6}{1}=6

Now that we know th eslope, we can start to fill out the equation. To find the y-intercept, we can plug in a given point and solve.

y=6x+b

1=6(-1)+b             [multiply]

1=-6+b                 [add both sides by 6]

b=7

Now, we know the equation is y=6x+7.

Stolb23 [73]3 years ago
6 0

Answer:

Step-by-step explanation:

(1+5)/(-1+2) = 6/1 = 6

y + 5 = 6(x + 2)

y + 5 = 6x + 12

y = 6x + 7

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Subtract: 4x/x^2-25 - 2/x^2+2x-15
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Answer: \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}

Step-by-step explanation:

Given

Subtract the expression

\Rightarrow \dfrac{4x}{x^2-25}-\dfrac{2}{x^2+2x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{x^2+5x-3x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{(x+5)(x-3)}\\\\\text{Take the LCM and subtract}\\\\\Rightarrow \dfrac{4x(x-3)-2(x-5)}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-12x-2x+10}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}

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