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3 years ago

Plz help.

1 answer:

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Aryabhata, also called Aryabhata I or Aryabhata the Elder, (born 476, possibly Ashmaka or Kusumapura, India), astronomer and the earliest Indian mathematician whose work and history are available to modern scholars. He is also known as Aryabhata I or Aryabhata the Elder to distinguish him from a 10th-century Indian mathematician of the same name. He flourished in Kusumapura—near Patalipurta (Patna), then the capital of the Gupta dynasty—where he composed at least two works, Aryabhatiya (c. 499) and the now lost Aryabhatasiddhanta.

Aryabhatasiddhanta circulated mainly in the northwest of India and, through the Sāsānian dynasty (224–651) of Iran, had a profound influence on the development of Islamic astronomy. Its contents are preserved to some extent in the works of Varahamihira (flourished c. 550), Bhaskara I (flourished c. 629), Brahmagupta (598–c. 665), and others. It is one of the earliest astronomical works to assign the start of each day to midnight.

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Aryabhatiya was particularly popular in South India, where numerous mathematicians over the ensuing millennium wrote commentaries. The work was written in verse couplets and deals with mathematics and astronomy. Following an introduction that contains astronomical tables and Aryabhata’s system of phonemic number notation in which numbers are represented by a consonant-vowel monosyllable, the work is divided into three sections: Ganita (“Mathematics”), Kala-kriya (“Time Calculations”), and Gola (“Sphere”).

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A circle has a diameter of 41 centimeters. Which equation can be used to find the radius of this circle?

Sati [7]

Answer:

Equation to find radius = Diameter divided by 2

Area is 1319.585

Step-by-step explanation:

Diameter = 41 cm

Radius = 41÷2 = 20.5cm

Area = πr^2

Area = 3.14×(20.5)^2

Area = 3.14×420.25

Area = 1319.585cm^2

7 0

3 years ago

Michael has a painting that is 3 inches wide by 18 inches long he made an enlarged copy of it do you large copy is 12 inches wid

deff fn [24]

Answer:

Step-by-step explanation:

9, because 18 multiplied by 3 is equal to 54

54 multiplied by 2 is equal to 108

And,

108 divided by 12 is 9.

7 0

3 years ago

Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applie

adoni [48]

Answer:

Location of T' on the coordinate axis will be (16,7).

T (6,4) → T' (16,7).

Step-by-step explanation:

coordinate vertices of points in rectangle JKLM are:

J (-8,-8)

K (-4,-8)

L (-4,-5)

M (-8,-5)

and coordinate vertices of points in rectangle J'K'L'M' are:

J' (2,-5)

K' (6,-5)

L' (6,-2)

M' (2,-2)

coordinate vertices of points in Quadrilateral STUV are:

S (1,4)

T (6,4)

U (4,6)

V (2,6)

transformation in coordinate vertices from rectangle JKLM to rectangle J'K'L'M' is:

J (-8,-8) → J' (2,-5)

⇒ along x axis -8 → 2 which means that rectangle is shifting towards right by 10 units.

and along y axis -8 → -5 which means that the rectangle is shifting upwards by 3 units.

similarly for

K (-4,-8) → K' (6,-5)

⇒ along x axis -4 → 6 which means that rectangle is shifting towards right by 10 units.

and along y axis -8 → -5 which means that the rectangle is shifting upwards by 3 units.

L (-4,-5) → L' (6,-2)

⇒ along x axis -4 → 6 which means that rectangle is shifting towards right by 10 units.

and along y axis -5 → -2 which means that the rectangle is shifting upwards by 3 units.

M (-8,-5) → M' (2,-2)

⇒ along x axis -8 → 2 which means that rectangle is shifting towards right by 10 units.

and along y axis -5 → -2 which means that the rectangle is shifting upwards by 3 units.

So, the location of T' of the Quadrilateral S'T'U'V' on the coordinate plane will be:

along x axis the Quadrilateral will shift towards right by 10 units

So, 6 → 6+10=16

and along y axis the Quadrilateral will shift upwards by 3 units

So, 4 → 4+3=7

⇒ T (6,4) → T' (16,7).

7 0

3 years ago

Read 2 more answers

What is the purpose of properties? for math<br><br><br> 20 points HELP ASAP!!!!!!!!

iren [92.7K]

Answer:

Remembering the properties of numbers is important because you use them consistently in pre-calculus. The properties aren't often used by name in pre-calculus, but you're supposed to know when you need to utilize them.

6 0

3 years ago

Will give you BRAINLEST

____ [38]

Answer:

Both boxes have the same amount of work applied to them. The smaller box will get to the end first.

Step-by-step explanation:

For the 400 kg box, we can say,

force = 1 newton

force = mass*acceleration

1 = 400*acceleration

acceleration = 1/400 meters per second^2

acceleration = 0.0025 meters per second^2

Each second, the larger box's velocity is increasing by 0.0025 meters per second.

While the smaller box would have an acceleration of...

force = 1 newton

force = mass*acceleration

1 = 200*acceleration

acceleration = 1/200 meters per second^2

acceleration = 0.005 meters per second^2

Which is twice as much as the larger box.

Put simply: if the force applied is the same for the two boxes, then the smaller box will have larger acceleration. This is because more force is needed to push on the larger mass.

Because the smaller box has more acceleration, it will naturally travel faster compared to the larger box. Therefore, the smaller box reaches the goal line faster.

7 0

3 years ago