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goldenfox [79]
1 year ago
11

A sealed container of N2 gas has a pressure of 836 kPa at 54.7 ∘ C. After it is left out in the sun the pressure increases by 79

.9 kPa. What is the new temperature of the container?
Chemistry
1 answer:
Anuta_ua [19.1K]1 year ago
5 0
P1=836kPa
T1=54.7+273=327.7K
P2=836+79.9=915.9kPa
T2=?
T2=T1*P2/P1
=327.7*915.9/836
=359K=86 degree celsius
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Answer:

108 kPa  

Step-by-step explanation:

To solve this problem, we can use the <em>Combined Gas Laws</em>:

p₁V₁/T₁ = p₂V₂/T₂             Multiply each side by T₁

   p₁V₁ = p₂V₂ × T₁/T₂      Divide each side by V₁

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Data:

p₁ = ?;                 V₁ = 34.3 L; T₁ = 31.5 °C

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(a) Convert temperatures to <em>kelvins </em>

T₁ = (31.5 + 273.15) K = 304.65 K

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(b) Calculate the <em>pressure </em>

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