Answer:
9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch
Step-by-step explanation:
Diameter of reamed hole = 0.278 inch
Radius of reamed hole = 
Surface area of reamed hole = 
Surface area of reamed hole = 
Surface area of reamed hole = 0.06066794
Diameter of pin = 
Radius of pin =
Surface area of pin = 
Since the surface area of pin is more than the surface area of hole .
So, a 9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch
I think you have to follow someone and ask them to be your tutor.
Answer:

Step-by-step explanation:

I am joyous to assist you at any time.
The function is f(x)=2x+10
Answer:
A
Step-by-step explanation:
ewqrui