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miv72 [106K]
2 years ago
15

Need help ASAP! Directions in picture ;)

Mathematics
2 answers:
Nat2105 [25]2 years ago
4 0

Answer:

m < 8 = 54.4°

Step-by-step explanation:

Fittoniya [83]2 years ago
4 0

Answer:

98°

Step-by-step explanation:

We know,

Angle 5 and angle 8 is supplementary and forms an angle of 180°.

So ,

<h3>According to the question</h3>

180 - 82 = angle \: 8

= 98

So answer is 92°

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If w is .47 and v is 13.5 then, 0.47=6.75Q
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The answer is 8 okay
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Helen [10]

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4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
Need help with my geometry h/w help pls.
Stella [2.4K]
Triangles
ABC - AB=2.5, BC=1.5, CA=2 (5: 3: 4)
ADC - AC=2, CD= 1.2, DA= 1.6
BCD - BC=1.5, BD = 0.9, DB = 1.2

Area
ABC = 1/2 *AC * CB = 1/2 *2 * 1.5 = 1.5 m^2
ADC = 1/2 *AD * DC = 1/2 * 1.6 * 1.2 = 0.96 m^2
BCD = 1/2 *BD * DC = 1/2 * 0.9 * 1.2 = 0.54 m^2

3 0
3 years ago
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