What are all the factors of 32? A 2, 4, 8, 16 B 1, 2, 16, 32 C 1, 2, 4, 8, 16, 32 D 2, 4, 6, 8, 12, 16, 32
Natasha2012 [34]
What are all the factors of 32?
answer : ( C ) 1, 2, 4, 8, 16 and 32.....
Answer:
it is 69
Step-by-step explanation:
do calculations
Answer:
4th option (sqrt(10))/2
Step-by-step explanation:
9514 1404 393
Answer:
k = -1
Step-by-step explanation:
Put the given value of x in the equation, and solve the resulting equation for k.
2(5 -3) +k(1 +2·5) = k - 5 - 1
2(2) +k(11) = k -6 . . . . simplify a bit
10k = -10 . . . . . . . . . . add -4-k to both sides
k = -1 . . . . . . . . . . . . . divide by 10
The value of k is -1.
_____
<em>Check</em>
Use k = -1 in the original equation and solve for x.
2(x -3) -(1 +2x) = -1 -x -1
2x -6 -1 -2x = -x -2 . . . . eliminate parentheses
x = 7 -2 = 5 . . . . . . add x+7; answer checks OK
Answer:
1) It is geometric
a) In each trial you can obtain 11 or obtain something else (and fail)
b) Throw 2 dices and watch if the result is 11 or not
c) The probability of success is 1/18
2) It is not geometric, but binomal.
Step-by-step explanation:
1) This is effectively geometric. When you see the sum of 2 dices, you can separate the result in two different outcomes: when the sum is 11 and when the sum is different from 11.
A trial is constituted bu throwing 2 dices and watching if the sum of the dices is 11 or not.
In order to get 11 you need one 5 in one dice and 1 six in another. As a consecuence, you have 2 favourable outcomes (a 5 in the first dice and a 6 in the second one or the other way around). The total amount of outcomes is 6² = 36, and all of them have equal probability. This means that the probability of success is 2/36 = 1/18.
2) This is not geometric distribution. The geometric distribution meassures how many tries do you need for one success. The amount of success in 10 trias follows a binomial distribution.
