To get the greatest possible quotient, you need the biggest possible
dividend and the smallest possible divisor.
96,432 divided by 225 = 428.5666... <== greatest possible
23,469 divided by 522 = 44.9597... <== smallest possible
9514 1404 393
Answer:
(a) M = 0.25n +100
Step-by-step explanation:
The distance between the dots on the graph is a rise of 1 grid square and a run of 2 grid squares. If we extend the sequence of dots to the left, we expect to place one at (0, 100). That is, the y-intercept of this function is 100 (eliminates choices C and D).
The rise of 1 grid square represents 25 kg, and the run of 2 grid squares represents 100 CDs. Then the slope of the function (rate of change) is ...
slope = rise/run = 25/100 kg/CD = 0.25
Then the equation describing the points on the graph will be ...
M = 0.25n +100
Answer:
i think its the third one
Step-by-step explanation:
Which is an arithmetic sequence?A)9, 12, 16, 20...B)9, 11, 13, 16...C)1, 5, 9, 13, 17...D)12, 14, 16, 18...
marta [7]
Answer: https://www.khanacademy.org/commoncore/grade-HSF-F-IF#HSF-IF.A.3
Step-by-step explanation:
copy and paste the link on to your search bar
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
