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miv72 [106K]
3 years ago
4

Why is it difficult to assign a numerical age to a sedimentary rock?

Chemistry
1 answer:
svetlana [45]3 years ago
4 0

Answer:

Explanation:

The order of occurrence of the sedimentary layer is related to a local igneous body that has been radiometrically dated, thus yielding an age range for the sedimentary layer.

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Which term is used to describe a molecule that has a partial positive charge at one end and a partial negative charge at the oth
nirvana33 [79]
These type of molecules are called dipoles 
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How does an open system differ from a closed system
Len [333]

Explanation:

A system can be either closed or open; A closed system is a system that is completely isolated from its environment. An open system is a system that has flows of information, energy, and/or matter between the system and its environment, and which adapts to the exchange.

7 0
3 years ago
What mass of propane (c3h8(g)) must be burned to supply 2775 kj of heat? the standard enthalpy of combustion of propane at 298 k
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Answer is: 55.125 grams <span>of propane must be burned.
</span>Balanced chemical reaction: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.
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5 0
4 years ago
two objects each have a mass of 5.0 g. one had a density of 2.7 g. and the other has a density of 8.4 g. which object has a larg
gulaghasi [49]

Answer:

The body with 2.7 \frac{g}{(cm^3)} has a larger volume

Explanation:

There is a missespelling in the question. The units of density cannot be g, they usually are \frac{g}{(cm^3)}

In order to answer this question, we need to use the formula of the density of a body:

Density = \frac{Mass}{Volume} = \frac{M}{V}

For body A:

Mass (M) = 5.0 g

Density (D) = 2.7 \frac{g}{(cm^3)}

2.7 \frac{g}{(cm^3)} = 5g * 1/V

V1 = 5g / (2.7 \frac{g}{(cm^3)})

V1 = 1.85 1.85 cm^3

For Body B:

Mass (M) = 5.0 g

Density (D) = 8.4 \frac{g}{(cm^3)}

8.4 \frac{g}{(cm^3)} = 5g * 1/V

V2 = 5g / (8.4 \frac{g}{(cm^3)})

V2 = 0.59 1.85 cm^3

So V1 is bigger than V2

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4 years ago
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Undergo radioactive decay
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