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Setler79 [48]
4 years ago
13

What mass of propane (c3h8(g)) must be burned to supply 2775 kj of heat? the standard enthalpy of combustion of propane at 298 k

is −2220 kj · mol−1 ?
Chemistry
1 answer:
Shalnov [3]4 years ago
5 0
Answer is: 55.125 grams <span>of propane must be burned.
</span>Balanced chemical reaction: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.
Make proportion: 1 mol(C₃H₈) : 2220 kJ = n(C₃H₈) : 2775kJ.
n(C₃H₈) = 2775 kJ·mol ÷ 2220 kJ.
n(C₃H₈) = 1.25 mol.
m(C₃H₈) = n(C₃H₈) · M(C₃H₈).
m(C₃H₈) = 1.25 mol · 44.1 g/mol.
m(C₃H₈) = 55.125 g.
n - amount of substance.
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The half life of a certain radioactive element is 1,250 years what percent of the atoms remain after 7500 years
andrezito [222]
Each half-life results in ~50% (1/2) of the original element remaining.

7500/1250 = 6 half-lives, so 100(1/2)^6
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7 0
3 years ago
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WILL MARK BRAINIEST
lions [1.4K]

<u><em>Answer:</em></u>

  • The correct option is B. The nonpolar substance has a lower boiling point than the polar substance.

<u><em>Explanation: </em></u>

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<em><u>Note</u></em>

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3 years ago
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At 570 mm hg and 25 c a gas sample has a volume of 2270 ml what is the final pressure at a volume of 1250 ml?
ValentinkaMS [17]

Main Answer:

Given data:

Initial Pressure P1 = 570 mm hg

Initial Volume V1 = 2270 ml

Final Pressure P2 = ? mm hg

Final Volume V1 = 1250 ml

According to the ideal gas equation,

PV = constant.

P1V1 = P2V2

P2 = P1V1/V2

P2 = (570 x 2270) / 1250

P2 = 1035.12 mm hg

The final pressure at volume of 1250 ml is 1035.12 mm hg.

Explanation:

What is ideal gas equation ?

The ideal gas equation is as follows:

PV = nRT

where P = Pressure

V = Volume

n = number of moles of gas

R = Universal gas constant

T = Temperature

This ideal gas equation provides the macroscopic particles behavior of the gas. At this condition, the particles of the gas, won't be attract or repel each other. It is consider as the stable condition.

To know more about ideal gas equation, please visit:

brainly.com/question/21912477

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deduce the formula of the compound that contains 2+ ions and 3- ions that both have the same electron configuration as argon
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\\ \sf\longmapsto [Ar]

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\\ \sf\longmapsto [Ar]^{2-}

  • The element will be Calcium

And

\\ \sf\longmapsto [Ar]^{3+}

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