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Answer:
1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.
Explanation:
Given data:
mass of cadmium = 6.35 g
Number of atoms of aluminum as 6.35 g cadmium contain = ?
Solution:
Number of moles of cadmium = 6.35 g/ 112.4 g/mol
Number of moles of cadmium = 0.06 mol
Number of atoms of cadmium:
1 mole = 6.022×10²³ atoms of cadmium
0.06 mol × 6.022×10²³ atoms of cadmium/ 1mol
0.36×10²³ atoms of cadmium
Number of atoms of Al:
Number of atoms of Al = 0.36×10²³ atoms
1 mole = 6.022×10²³ atoms
0.36×10²³ atoms × 1 mol /6.022×10²³ atoms
0.06 moles
Mass of aluminum:
Number of moles = mass/molar mass
0.06 mol = m/ 27 g/mol
m = 0.06 mol ×27 g/mol
m = 1.62 g
Thus, 1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.
Answer:
B) copper.
Explanation:
The reaction: Zn + Cu²⁺ → Zn²⁺ + Cu.
Zn losses 2 electrons and converts to Zn²⁺.
Cu²⁺ gains 2 electrons and converts to Cu.
So, the electron acceptor element is copper.
The right choice is: B) copper.
The mass of ethanol is consumed by the reaction of 3.37g oxygen gas is 4.85g
Explanation:
The balanced equation for the chemical reactions is;
CH₃CH₂OH + O₂ → CH₃COOH + H₂O
The mole ratio between oxygen and ethanol in the reaction is 1 : 1
The molar mass of O₂ is 32g / mole. Therefore the O₂ moles consumes in the reaction is;
3.37 / 32
If the molar mass of ethanol is 46.07g/mole, and the ration of reaction in 1 : 1; Then the moles of ethanol consumed is;
3.37/32 * 46.07
= 4.85g
