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2 years ago

Arthur bought a life insurance policy at $10.98 per month for a 20 year term. What will he pay over 20 years for the premium?

Mathematics

2 answers:

Brut [27]2 years ago

6 0

Arthur will pay $2635.20 for 20 years for premium

andre [41]2 years ago

5 0

12(months) x 20 (years) = 240

10.98 x 240 = 2635.20

So Arthur will pay $2635.20 over 20 years for premium.

I hope this helps :)

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Answer:

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Order of Operations: BPEMDAS

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Parenthesis
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Determine n between 0 and 19 such that (2311)(3912) ≡ n mod 20.

sleet_krkn [62]

You can write 2311 and 3912 in the form $20q+r$ :

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Then

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Taken modulo 20, the terms containing powers of 20 vanish and you're left with

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so we end up with

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###

If instead you're trying to find $2311^{3912}\pmod{20}$ , you can apply Euler's theorem. We can show that $\mathrm{gcd}(2311,20)=1$ using the Euclidean algorithm. Then since $\varphi(20)=8$ , and 8 divides 3912, we have

$2311^{3912}\equiv2311^{489\cdot8}\equiv(2311^{489})^8\equiv1\pmod{20}$

To show 2311 and 20 are coprime:

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20 = 1*11 + 9

11 = 1*9 + 2

9 = 4*2 + 1 => gcd(2311, 20) = 1

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