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exis [7]
2 years ago
11

Please help me i dont understand

Mathematics
2 answers:
inn [45]2 years ago
8 0

Answer:

you are multiplying by 7

Step-by-step explanation:

so like 3 x 7 = 21

4 x 7 = 28

6 x 7 = 42

9 x 7 = 63

10 x 7 = 70

hope it helps

Viktor [21]2 years ago
8 0

7,9

Step-by-step explanation:

3x4=21

4x7=28

6x7=42

9x7=64

10x7=70

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Given the following function, find f(-2), f(0), and f(4).
borishaifa [10]

Answer:

f(-2) = 0

f(0) = -4

f(4) = 12

Step-by-step explanation:

Given the function f(x) = x^2 - 4, we must plug in the values substituting x for each of the answers.

f(-2) = (-2)^2 - 4

-2 times itself is a positive 4, therefore:

f(-2) = 4 - 4

f(-2) = 0

We do the same for each answer.

f(0) = (0)^2 - 4

f(0) = -4

f(4) = (4)^2 - 4

f(4) = 16 - 4

f(4) = 12

6 0
3 years ago
What is the distance between the points?! round to the nearest tenth i need to show work
Contact [7]

Answer:

8.6

Step-by-step explanation:

To find the distance between two points we use the formula posted below

All we need to do is figure out what the points are on the graph and plug them into the formula... we end up with

the square root of (5-(-2)^2+(2-(-3)^2 and get the answer of 8.602325267

then we round to the nearest tenth and get 8.6

5 0
3 years ago
Solve for b.<br> 3b &lt; 9<br> 23<br> Submit
Margarita [4]

Answer:

b>3

Step-by-step explanation:

4 0
2 years ago
HELP! Find the value of sin 0 if tan 0 = 4; 180 &lt; 0&lt; 270
BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

  • sinθ = -4sqrt(17)/17 or A choice.
4 0
3 years ago
What are the factors of 32?
Mumz [18]
The factors of 32 is 1,2,4,8,16, and 32.

7 0
2 years ago
Read 2 more answers
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