Answer:
2 unit/time²
Step-by-step explanation:
Given the equation:
v(t) =t^2-3t
At interval ; 1, 4
V(1) = 1^2 - 3(1)
V(1) = 1 - 3
V(1) = - 2
At t = 4
V(4) = 4^2 - 3(4)
V(4) = 16 - 12
V(4) = 4
Average acceleration : (final - Initial Velocity) / change in time
Average acceleration = (4 - (-2)) ÷ (4 - 1)
Average acceleration = (4 + 2) / 3
Average acceleration = 6 /3
Average acceleration = 2
Answer:
16,244.26
Step-by-step explanation:
14,187.13 + (14.5% × 14,187.13) =
14,187.13 + 14.5% × 14,187.13 =
(1 + 14.5%) × 14,187.13 =
(100% + 14.5%) × 14,187.13 =
114.5% × 14,187.13 =
114.5 ÷ 100 × 14,187.13 =
114.5 × 14,187.13 ÷ 100 =
1,624,426.385 ÷ 100 =
16,244.26385 ≈
Answer:
I think the D equals one (1) based on the info i was given
Step-by-step explanation:
Answer:
???
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
12/5
Discussion:
Note that 10 is a common denominator of both denominators:
9/5 = (9*2)/(5*2) = 18/10
- ( -6/10) = + (6/10)
So the original problem is equivalent to
18/10 + 6/10 =
(18 +6)/10 =
24/10 =
(2*12)/ (2*5) => cancelling the common factor "2"
12/5 =
2 and 2 fifths =
22/5 (though this looks like (22)/5!)
Thank you,
MrB
