The solution would be like this for this specific problem:
For freezing point
Tf, soln= -114.6-(i*Kf*m)
Tf, soln= -114.6 - (1*1.99*0.40)
Tf= -115.4 C
For boiling point:
Tb=78.4+(i*Kf*m)
Tb=78.4+(1*1.99*.40)
Tb= 79.2 C
So the boiling and freezing point of a 0.40m solution of sucrose in ethanol is 79.2 C and -115.4 C respectively.
5,500 written as 5.5 x 103 in scientific notation. hope i helped
The only liquid elements at standard temperature and pressure are bromine (Br) and mercury (Hg). Although, elements caesium (Cs), rubidium (Rb), Francium (Fr) and Gallium (Ga) become liquid at or just above room temperature.
I searched it up and got 0.065
