1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dominik [7]
1 year ago
11

The delocalized cloud of π electrons in benzene is formed by the overlap of 6 ________ orbitals.

Chemistry
1 answer:
Radda [10]1 year ago
8 0

The delocalized cloud of π electrons in benzene is formed by the overlap of 6<u> p-orbitals</u>.

So, option B is correct one.

In the case of hydrocarbons, delocalisation occurs in benzene rings , where a hexagon of six carbon atoms has decalized electrons spread over the whole ring.

All of the carbon atoms in the benzene rings are sp^{2} orbitals around the ring produces a framework of six sigma bonds, while the unhybridized p-orbitals which are perpendicular to this plane over in side-to-side fashion to form three pi-bonds.

To learn more about benzene

brainly.com/question/14525517

#SPJ4

You might be interested in
20 POINTS!! please helps me with this word bank!! due today!! you can use a word more than once please help
Bogdan [553]

Answer:

zoom in please i cant see

Explanation:

7 0
3 years ago
Read 2 more answers
How many moles are present in
olasank [31]

Answer: (a) There are 0.428 moles present in 12 g of N_{2} molecule.

(b) There are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of N_{2} is 28 g/mol so its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol

So, there are 0.428 moles present in 12 g of N_{2} molecule.

(b). According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

Therefore, moles present in 12.044 \times 10^{23} particles are calculated as follows.

Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol

So, there are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

4 0
2 years ago
A gas with a volume of 500. mL at 75°C is heated to 225 °C. What is the new volume of the gas?
mihalych1998 [28]
Using v1/t1=v2/t2
v1=500
v2=?
t1=75=368k
t2=225=498
500/368=v2/498
1.4x498=v2
v2=697.2ml
6 0
2 years ago
ASAPPP EASY!!!!!!!!!!
zhenek [66]
Did you know conventional argult culture has increased greenhouse gas emissions, soil erosion, water pollution, and threatened humans health. Let’s stop this from harming our environment and take action about this today. Organic farming has a smaller carbon footprint, conserves and builds soil, replenishes natural ecosystems for cleaner water and air, all with a toxic pesticide residues.
5 0
3 years ago
Write a complete, balanced chemical equation where tin metal reacts with aqueous hydrochloric acid to produce tin(II) chloride a
AleksAgata [21]

Answer:

1. The balanced equation is given below:

Sn (s) + 2HCl (aq) –> SnCl₂ (aq) + H₂ (g)

2a. H is oxidized.

2b. Sn is reduced.

Explanation:

1. Balanced equation for the reaction between tin (Sn) metal and aqueous hydrochloric acid (HCl) to produce tin(II) chloride (SnCl₂) and hydrogen gas (H₂).

This is illustrated below:

Sn (s) + HCl (aq) –> SnCl₂ (aq) + H₂ (g)

There are 2 atoms of Cl on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:

Sn (s) + 2HCl (aq) –> SnCl₂ (aq) + H₂ (g)

Now, the equation is balanced

2. Determination of the element that is oxidize and reduced.

This can be obtained as follow:

We shall determine the change in oxidation number of each element.

NOTE:

a. The oxidation number of H is always +1 except in hydrides where it is –1.

b. The oxidation state of Cl is always –1.

Sn (s) + 2HCl (aq) –> SnCl₂ (aq) + H₂ (g)

For Tin (Sn):

Sn = 0

SnCl₂ = 0

Sn + 2Cl = 0

Cl = – 1

Sn + 2(–1) = 0

Sn – 2 = 0

Collect like terms

Sn = 0 + 2

Sn = +2

Therefore, the oxidation number of Tin (Sn) changes from 0 to +2

For H:

H = +1

H₂ = 0

The oxidation number of H changes from +1 to 0

For Cl:

Cl is always –1. Therefore no change.

Summary:

Element >>Change in oxidation number

Sn >>>>>>>From 0 to +2

H >>>>>>>>From +1 to 0

Cl >>>>>>>No change

Therefore,

Sn is reduced since its oxidation number increased from 0 to +2.

H is oxidized since it oxidation number reduced from +1 to 0

4 0
2 years ago
Other questions:
  • How should a stopper be handled after is has been removed from a reagent bottle?
    10·1 answer
  • how was it possible that Mendeleev was able to predict the properties of elements that no one knew about
    12·1 answer
  • A teacher makes the following statement.
    9·2 answers
  • 2.25 g/ml at 700mmHg, 200 C. Find molar mass of gas.
    15·1 answer
  • Which is not a layer found in the earth's mantle? A. Upper mantle B. asthenosphere C. lithosphere D.crust
    13·1 answer
  • How many molecules are in 2.00 mol of water?
    11·1 answer
  • Newton's first law of motion says that an object in motion will remain in
    7·1 answer
  • A scientist is using robots to perform thousands of experiments on different
    6·1 answer
  • The phase change between white tin and gray tin is difficult to observe directly. Both substances can be burned, however. From t
    14·1 answer
  • Which would have the highest first ionization energy?
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!