Answer:
5.9 g/cm³
Step-by-step explanation:
Data:
Mass of metal = 43.98 g
Initial level of water = 13.8 mL
Final level of water = 21.3 mL
Calculations:
The picture below illustrates what's happening in this experiment.
The water level was originally at 13.8 mL.
Then you added the metal. It fell to the bottom and displaced its volume of water.
The water level rose to 21.3 mL, so
Volume of metal = volume of displaced water
= 21.3 mL – 13.8 mL
= 7.5 mL
= 7.5 cm³
Density = mass/volume
= 43.98/7.5
= 5.9 g/cm³
Answer:
First statement is true:
- <u><em>NH₄ would be expected to have polar covalent bonds with a partial positive charges on the H atoms.</em></u>
Explanation:
Nitrogen (N) and hydrogen (H) are two nonmetals; thus, it should be a hint to assert that they form a covalent bond.
The difference in <em>electronegativities</em> between<em> N</em> and <em>H </em>is <em>3.0</em> - <em>2.1</em> = 0.9.
That makes that the bonds be <em>polar</em>. Ions are not formed because to transfer the electrons from one atom to the other (to form ionic bonds) requires an electronegativity difference greater than about 1.7.
Since N is more electronegative than H, in the molecule <em>NH₄</em>, each N atom will pull the electron density toward itself acquiring a partial negative charge and leaving H atoms with a partial positive charge.
Thus, each NH bond is<em> polar covalent with a partial positive charge on the H atoms</em> (first statement from the choices).
YES I think it can that is a really good question I'm gonna rate you 5 stars for that question that was the best question ive ever had lol
We need a image to answer this sorry
Answer:
1.1 percent
Explanation:
C6H5COOH⇌C6H5COO+H
Ka = [C6H5COO-][H+]/[C6H5COOH]
From pKa of 4.2, Ka = 6.3x10^-5
6.3x10^-5 = (x)(x)/0.51-x and assuming x is small...
6.3x10^-5 = x^2/0.51
x^2 = 3.213x10^-5
x =5.67 x10^-3
(5.67x10^-3/0.51)x 100 =1.1 percent
