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ivolga24 [154]
3 years ago
12

A man took a loan of GHC 1,800.00 at an interest of 12½ percent per annum. It was agreed that the loan and interest must be paid

in one-year monthly installment. Calculate
a) the interest of the loan.

b) the amount to be paid at the end of the year.

c) the monthly installment.

Please help. A persuasive question.

Please no links and unnecessary answers. ​
Mathematics
1 answer:
diamong [38]3 years ago
4 0

Answer:

Hi. I'm sorry, I don't know.

You might be interested in
Please help me with this! <3
alexandr402 [8]

Answer:

Surface Area=

100\pi

  1. 4\pi \times  {r}^{2}  = 100\pi
  2. r=5

7 0
3 years ago
consider the exponential function g(x)=100 x (2). which of the following situations could be modeled by the function?
daser333 [38]
The initial value of 100 that doubles over each interval.
without the answer choices, I can only describe it and give you an example of the graph. 
I'm assuming the function is 100*(2)^x because if it is as listed it would be a quadratic function with a vertical stretch of 100.

3 0
4 years ago
Write the inverse function for the function, ƒ(x) = x + 4. Then, find the value of ƒ -1(4). Type your answers in the box.
KATRIN_1 [288]
F(x)^-1=x-4
f(4)^-1=0
8 0
3 years ago
Every day for 5 days Jack and Jill went walking. Each day Jack walked 4/5 of a mile and Jill walked 2/3 of a mile. At the end of
DanielleElmas [232]

\bf \stackrel{\textit{Jack for 7 days}}{7\left( \cfrac{4}{5} \right)}\implies \cfrac{28}{5}~\hspace{10em}\stackrel{\textit{Jill for 7 days}}{7\left( \cfrac{2}{3} \right)}\implies \cfrac{14}{3}
\\\\[-0.35em]
~\dotfill\\\\
\cfrac{28}{5}-\cfrac{14}{3}\implies \stackrel{\textit{LCD of 15}}{\cfrac{(3)28-(5)14}{15}}\implies \cfrac{84-70}{15}\implies \cfrac{14}{15}

7 0
3 years ago
Find the sum of the first six terms of a geometric series in which a1 = 4 and r = -3: A. 729 B. -729 C. -728 D. 728 plz help
natta225 [31]

Answer:

C

Step-by-step explanation:

The sum to n terms of a geometric sequence is

S_{n} = \frac{a_{1}(r^n-1) }{r-1}

Here a₁ = 4 and r = - 3, thus

S_{6} = \frac{4((-3)^6-1)}{-3-1}

    = \frac{4(729-1)}{-4} = - (729 - 1) = - 728 → C

6 0
3 years ago
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