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ivolga24 [154]
3 years ago
12

A man took a loan of GHC 1,800.00 at an interest of 12½ percent per annum. It was agreed that the loan and interest must be paid

in one-year monthly installment. Calculate
a) the interest of the loan.

b) the amount to be paid at the end of the year.

c) the monthly installment.

Please help. A persuasive question.

Please no links and unnecessary answers. ​
Mathematics
1 answer:
diamong [38]3 years ago
4 0

Answer:

Hi. I'm sorry, I don't know.

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What are the roots to this quadratic equation?
myrzilka [38]
16x^2=9
x^2=9/18
x=sqrt(9/16)
x=3/4,-3/4
so the root of the quadratic equation are 3/4 and -3/4 
5 0
3 years ago
6th grade math plz help
ella [17]

Answer:

The question needs more information but you can see that all the numbers in the 1st column are multiplied by 6 to equal the number in column 2

Step-by-step explanation:

3 x6 =18

6 x 6= 36

9 x6= 54

12 x6 =72

6 0
3 years ago
How do you change 24 2\5 into decimal?
seropon [69]
24 and 2/5=24+2/5
24=24

0.1=1/10
2/5=x/10
times both sides by 10
20/5=x
4=x
2/5=4/10=0.4


24 and 2/5=24+0.4=24.4
5 0
3 years ago
Read 2 more answers
Please help.................................................................................................
Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

L = 3*w + 1                      Given

P = 2*(L + w)                   Formula for Perimeter. Substitute for L    

P = 2*(3w + 1 + w)           Combine

P = 2*(4w + 1)                  

P = 58                             Given

58 = 8w + 2                    Remove the brackets

58 - 2 = 8w                     Subtract 2

56 = 8*w                         Divide by 8

56/8 = w

7 = w

================

Find L

L = 3*w + 1

L = 3*7 + 1

L = 22

================

Check

2L + 2W  = 58

2*22 + 2*7 =? 58

44 + 14 = ? 58

58 = 58

The answer checks.

5 0
3 years ago
Integrate x+1/sqrt(x). I know that the answer is 2/3 • sqrt(x) • (x+3) + C, but I don't know how it is simplified from 2/3 • x^3
Andreas93 [3]

\displaystyle\int\frac{x+1}{\sqrt x}\,\mathrm dx=\int\frac x{x^{1/2}}+\frac1{x^{1/2}}\,\mathrm dx

=\displaystyle\int x^{1/2}+x^{-1/2}\,\mathrm dx

By the power rule,

=\dfrac{x^{3/2}}{\frac32}+\dfrac{x^{1/2}}{\frac12}+C

(this seems to be the step you're not getting?)

=\dfrac23x^{3/2}+2x^{1/2}+C

The next step is to pull out a common factor of x^{1/2} from the antiderivative:

x^{3/2}=x^{1/2+1}=x^{1/2}\cdot x^1

so that the final result is

\dfrac23x^{3/2}+2x^{1/2}+C=\dfrac23x^{1/2}(x+3)+C

3 0
3 years ago
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