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Nonamiya [84]
2 years ago
15

Find the sum of the first six terms of a geometric series in which a1 = 4 and r = -3: A. 729 B. -729 C. -728 D. 728 plz help

Mathematics
1 answer:
natta225 [31]2 years ago
6 0

Answer:

C

Step-by-step explanation:

The sum to n terms of a geometric sequence is

S_{n} = \frac{a_{1}(r^n-1) }{r-1}

Here a₁ = 4 and r = - 3, thus

S_{6} = \frac{4((-3)^6-1)}{-3-1}

    = \frac{4(729-1)}{-4} = - (729 - 1) = - 728 → C

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