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steposvetlana [31]
2 years ago
14

Every day for 5 days Jack and Jill went walking. Each day Jack walked 4/5 of a mile and Jill walked 2/3 of a mile. At the end of

the week, how much further had Jack walked than Jill?
Mathematics
1 answer:
DanielleElmas [232]2 years ago
7 0

\bf \stackrel{\textit{Jack for 7 days}}{7\left( \cfrac{4}{5} \right)}\implies \cfrac{28}{5}~\hspace{10em}\stackrel{\textit{Jill for 7 days}}{7\left( \cfrac{2}{3} \right)}\implies \cfrac{14}{3}
\\\\[-0.35em]
~\dotfill\\\\
\cfrac{28}{5}-\cfrac{14}{3}\implies \stackrel{\textit{LCD of 15}}{\cfrac{(3)28-(5)14}{15}}\implies \cfrac{84-70}{15}\implies \cfrac{14}{15}

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gogolik [260]
The answer i B just finished this.
4 0
2 years ago
A boat is sighted from a 50-meter observation tower on the shoreline at an angle of depression of 4 degrees moving directly towa
MAXImum [283]

Answer:

  5.76 km/h

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationship between angles and sides of a right triangle. Here, we are given the side opposite the angle (angle of depression), and we want to find the adjacent side (distance from shore).

  Tan = Opposite/Adjacent

  tan(4°) = (height of tower)/(distance from shore)

  tan(4°) = (50 m)/(distance from shore)

Then the distance from shore is ...

  distance from shore = (50 m)/tan(4°) ≈ 715.03 m

__

At the second sighting, the distance from shore is ...

  distance from shore = (50 m)/tan(12°) ≈ 235.23 m

So, the distance traveled in 1/12 hour is ...

  715.03 m - 235.23 m = 479.80 m

and the speed in km per hour is ...

  speed = 0.4798 km/(1/12 h) = 5.7576 km/h

The speed of the boat is about 5.76 km per hour.

4 0
3 years ago
Which equations are correct? select three options. n = 10 n = 7 cf = 59 fe = 42 cd = 30
pashok25 [27]

Based on the calculations on this parallelogram, the correct equations are:

  1. n = 10
  2. CF = 59
  3. FE = 42

<h3>The properties of a parallelogram.</h3>

Based on the image of the parallelogram shown in the image attached below, we can logically deduce that the opposite sides of this parallelogram are all equal. Thus, we have:

Side DE = Side CF

6n - 1 = 5n + 9

6n - 5n = 9 + 1

n = 10.

From Side CF, we have:

CF = 5n + 9

CF = 5(10) + 9

CF = 59.

For the measure of side FE, we have

FE = 4n + 2

FE = 4(10) + 2

FE = 42.

Read more on parallelogram here: brainly.com/question/16743544

#SPJ1

Complete Question:

Figure CDEF is a parallelogram.

Parallelogram C D E F is shown. The length of F C is 6 n minus 1, the length of C D is 4 n + 2, and the length of D E is 5 n + 9.

Which equations are correct? Select three options.

n = 10

n = 7

CF = 59

FE = 42

CD = 30

5 0
1 year ago
Helpp please find the value of s! I will give brainlist
goldenfox [79]

We have :

s - 39⁰+ s - 9⁰ = s + 29⁰

s + s - s = 29⁰ + 9⁰ + 39⁰

s = 77⁰

Answer: 77⁰

Ok done. Thank to me :>

8 0
2 years ago
An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref
hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}

So the cost of laying pipe under water with this distance is

800000\sqrt{(3 - d)^2 + 4}

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

800000\sqrt{(3 - d)^2 + 4} + 400000d

We can find the minimum value of this by taking the 1st derivative and set it to 0

800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0

We can move the first term over to the right hand side and divide both sides by 400000

1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}

\sqrt{(3 - d)^2 + 4} = 6 - 2d

From here we can square up both sides

(3 - d)^2 + 4 = (6 - 2d)^2

9 - 6d + d^2 + 4 = 36 - 24d + 4d^2

3d^2-18d+27 = 0

d^2 - 6d + 9 = 0

(d - 3)^2 = 0

d -3 = 0

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0
3 years ago
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