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emmasim [6.3K]
3 years ago
6

Please help right away.

Mathematics
1 answer:
worty [1.4K]3 years ago
4 0
If you need an explanation please ask, but basically solve for y with the given equation

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Hey can you please help me posted picture of question
Temka [501]
The correct answer  for the problem shown in the figure atttached is the last option (option D), which is shown below:

 D.(-x-9i)(x-9i)

 If you want to verify that the option D.(-x-9i)(x-9i) is the correct answer, you can apply the distributive property to (-x-9i)(x-9i).

 Therefore, when you apply the distributive property, you obtain that the result is:

 -x²-81

 The graph attached shown this equation, which is a parabola.

4 0
4 years ago
Read 2 more answers
What’s the expanded form of 0.917
Paha777 [63]
(0.9) +(0.01) + (0.007)
4 0
4 years ago
7) y is inversely proportional to the square root of (x + 1).
Virty [35]
Mark Brainliest please

Answer y= 16/99

Explanation:
the initial statement is
y ∝ 1/x

To convert to an equation multiply by k the constant of variation
⇒ y = k × 1/x = k/x
To find k use the given condition y = 15 when x = 5

y = k/ x

⇒ k = y*x = 8 * 2 =16

equation is
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

y = 16/ x

when
x = 99
then

y = 16/99

Y = 16/99
3 0
3 years ago
Please help me pls and thank you!!
frosja888 [35]

Answer:

umm i don't see anything did i miss the joke lol

Step-by-step explanation:

3 0
3 years ago
Find all the values of x (where 0 < or equal to x and x < pi/2) in terms of pi for which cos(6x)=0
statuscvo [17]
         cos(6x) = 0
cos⁻¹[cos(6x)] = cos⁻¹(0)
                 6x = 90
                  6      6
                    x = 15°
                    x = ¹/₁₂π radians

         cos(6x) = 0
<span>cos⁻¹[cos(6x)] = cos⁻¹(0)
</span>                 6x = 270
                  6       6
                    x = 45
                    x = ¹/₄π radians

         cos(6x) = 0
<span>cos⁻¹[cos(6x)] = cos⁻¹(0)
</span>                 6x = 450
                  6       6
                    x = 75
                    x = ⁵/₁₂π radians
5 0
3 years ago
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