Answer:
Fill the gaps in this sequence:
25 36 <u>49</u> 64 81 <u>100</u>
This sequence is the numbers 5, 6, 7, 8, 9, and 10 squared.
Work out the cube root of 343, then square it.
<u>49</u>
Since 7 cubed equals 343, then 7 squared is 49.
When you subtract one square number from another the answer is 7.
What are the two square numbers?
<u>16</u> and <u>9</u>
These are the only squares that fit the criteria.
Write down a number you can square to give an answer bigger than 200 but smaller than 300.
<u>15, 16, 17</u>
All of those answers work. 15² is 225, 16² is 256, and 17² is 289. You can choose any of them to enter in and it should work.
Answer:
15 square meters
Step-by-step explanation:
when it says find the area you have to add all the lengths together
The error made by Tnaya in constructing the box plot is the first quartile and third quartile depicited is wrong.
<h3>What is a box plot?</h3>
A box plot is used to study the distribution and level of a set of data. The box plot consists of two lines known as whiskers and a box. The first whisker represents the minimum value and the last whisker represents the maximum value.
On the box, the first line to the left represents the first quartile. 25% of the score represents the lower quartile. The next line on the box represents the median. 50% of the score represents the median. The third line on the box represents the third quartile. 75% of the scores represents the third quartile.
For the data given, the:
- Minimum value = 12
- Maximum value = 22
- Median = 16
- First quartile = 11/4 = 2.75 = 13
- Third quartile = 3/4 x 11 = 8.25 = 23
To learn more about median, please check: brainly.com/question/20434777
Answer:
The value of c = -0.5∈ (-1,0)
Step-by-step explanation:
<u>Step(i)</u>:-
Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]
<u> Mean Value theorem</u>
Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

<u>Step(ii):</u>-
Given f(x) = 4x² +4x -3 …(i)
Differentiating equation (i) with respective to 'x'
f¹(x) = 4(2x) +4(1) = 8x+4
<u>Step(iii)</u>:-
By using mean value theorem


8c+4 = -3-(-3)
8c+4 = 0
8c = -4

c ∈ (-1,0)
<u>Conclusion</u>:-
The value of c = -0.5∈ (-1,0)
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