The first table is proportional. Y is 4 times X. The second table is 1.25 times X
Answer:
0
Step-by-step explanation:
-4 times -6x is 24x and-4 x -3 = 12
isolating 24x on the right side we subtract twelve on the right and on the left to get 24x=0 and 24 divided by zero is 0
Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
We're looking for C(h), where h is the hundreds of shirts. The fact that they cost "$500 for each additional 100 t-shirt" tells us the slope is 500. Knowing that 1 hundred costs 750, we could use point-slope at this point: (C - 750)/(h - 1) = 500C - 750 = 500h - 500C(h) = 500h + 250 We can check that C(1) = 750 and C(2) = 1250, as we expect. I'll leave it to you to evaluate C(5).