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loris [4]
3 years ago
5

The distance versus time graph for Object A and Object B are shown.

Physics
2 answers:
barxatty [35]3 years ago
8 0
Object B but not objective A
agasfer [191]3 years ago
3 0
2nd one , hshsjsehgehe
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Is lateral shift or lateral displacement same ?
xxMikexx [17]

Answer:

When a ray of light passes through a glass slab of a certain thickness, the ray gets displaced or shifted from the original path. This is called lateral shift/displacement.

Explanation:

.

7 0
3 years ago
Suppose a soccer player kicks the ball from a distance 29 m toward the goal. find the initial speed of the ball if it just passe
Rudik [331]

The ball's vertical velocity at the time it just passes over the goal is 0 m/s. Its initial vertical velocity is unknown and we denote it by v\sin39^\circ, where v here is the ball's initial speed. Vertically, the only force acting on the ball is gravity, which attributes a downward acceleration of 9.8 m/s^2. We expect the maximum height achieved by the ball to be 2.4 m, so we can find the initial speed by solving

\left(0\,\dfrac{\mathrm m}{\mathrm s}\right)^2-\left(v\sin39^\circ\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm m)

\implies v=11\,\dfrac{\mathrm m}{\mathrm s}

6 0
3 years ago
Write one advantage of MKS system over CGS system.​
Temka [501]
More convenient
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7 0
3 years ago
A que profundidad esta nadando una persona dentro de una alberca si la presión absoluta sobre ésta es de 156kPa?
lara31 [8.8K]

Answer:

La persona está nadando en la alberca a una profundida de 5.575 metros.

Explanation:

La presión absoluta (P_{tot}) experimentada por la persona es la suma de la presión atmosférica (P_{atm}) y la presión hidrostática de la columna de agua de la alberca (P_{h}), medidas en kilopascales. Es decir,

P_{tot} = P_{atm}+P_{h} (1)

P_{tot} = P_{atm} + \frac{\rho\cdot g \cdot z}{1000} (2)

Donde:

\rho - Densidad del fluido de la alberca, medida en kilogramos por metro cúbico.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

z - Profundidad de la persona en la alberca, medida en metros.

Si sabemos que P_{atm} = 101.325\,kPa, \rho = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}} y P_{tot} = 156\,kPa, entonces la profundidad de la persona en la alberca es:

156 = 101.325 +\frac{(1000)\cdot (9.807)\cdot z}{1000}

54.675 = 9.807\cdot z

z = 5.575\,m

La persona está nadando en la alberca a una profundida de 5.575 metros.

5 0
3 years ago
What is the solution set of the equation 3|5 -x| + 2 = 29?
Flura [38]
D. is the answer to that
3 0
3 years ago
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