X²/9 + y²/16 = 1
The general for mula of an ellipse is:
(x-h)²/a² + (y-k)²/b² = 1. Since h = k = 0, this ellipse
x²/9 + y²/16 = 1
passes by the center O. (Note that a = 3 and b = 4)
Moreover sin b>a so the majore axis is (on the y-axis) and a the minor axis (on the x-axis) [Its shape is as a vertical egg].
On a system of perpendicular axis that intercept in O., take on the x-axis 2 points A & B with respective coordinate A(3.0) and B(-3,0)
On the y-axis your report A'(0,+4) and B'(0,-4). So you have the vertex of the ellipse, then it's easy to draw it
Answer:a^2+2ab+b^2
Step-by-step explanation:
First write it out in extended form, (a+b)(a+b) then multiply each term by the other in each parenthesis, such as a*a+b*b+a*b+a*b
Then, once you have done that, simplify it. you will then get the answer a^2+2ab+b^2
Y=3x-4
Because your slope is 3 when you do change in y over change in x. Y intercept is neg 4.
Y = 12.1% x 13 + 351
y= 0.012 x 13 + 351
y= 1.573 + 351
y= 352.573 or $352.6
