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Bess [88]
2 years ago
14

In a rectangle the ratio of the length to the width is 5/6. If the width is 30, find the length.

Mathematics
2 answers:
beks73 [17]2 years ago
7 0

\huge{\textbf{\textsf{{\color{navy}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}

let length of the rectangle be x

so, from the question

\frac{5}{6}  =  \frac{x}{30}  \\

by cross multiplication,

150 = 6x \\ x =  \frac{150}{6}  \\ x = 25

<h2>x = 25.</h2>

  • Thanks
  • Hope it helps
Over [174]2 years ago
4 0

Answer:

the length of the rectangle is 25

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Simplify the ratio of 35:14
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Step-by-step explanation:

35 : 14

Divide by 7

5 : 2

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Explain how to get the variable alone in the equation. a ÷ 11 =5​
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Multiply both sides by 11 to isolate the variable.

Step-by-step explanation:

a = 55

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A team of runners is needed to run a 1/4 mile relay race. If each runner must run 1/16 mile how many runners will be needed?
myrzilka [38]
The answer is 4. If the relay is 1/4 mile, and each person runs 1/16 mile, then to get the answer you divide 1/4 by 1/6 and get 4. 4 people would be needed to run this relay. Hope this helps! :)
7 0
3 years ago
Read 2 more answers
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

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zepelin [54]

Answer:

P = 2x + 150

Step-by-step explanation:

P = 2x + 150

8 0
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