Since we tossed 2 dice, the sample space : 6 x 6 = 36 outcomes: {(1,1), (1,2),(1,3),(1,4),(1,5),(1,6) {(1,2),(2,2),(3,2),(4,2),(5,2)),(6,2) {------------------------------------------ ----------------------------------------- {(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}
What are the number that their sum is equal to 5: 1+4 =5 4+1 =5 2+3 =5 3+2 =5
Total favorable outcomes = 4:
So the probability of getting a sum of 5 is P(sum=5) = 4/36 = 1/9 = 0.111
