Question

We preform the experiment "toss two dice". What is the probability of the event "the sum of the faces equals 5"?

Answer 1

Since we tossed 2 dice, the sample space : 6 x 6 = 36 outcomes:
{(1,1), (1,2),(1,3),(1,4),(1,5),(1,6)
{(1,2),(2,2),(3,2),(4,2),(5,2)),(6,2)
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{(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}

What are the number that their sum is equal to 5:
1+4 =5
4+1 =5
2+3 =5
3+2 =5

Total favorable outcomes = 4:

So the probability of getting a sum of 5 is P(sum=5) = 4/36 = 1/9 = 0.111

Answer 2

Answer: 4/36

Step-by-step explanation: Count how many times a black 5 shows up. Divide that over 36