Answer:
A = (16π - 8) cm^2
Step-by-step explanation:
The shaded area is trhe area of the circle minus rthe area of the truiangle,.
A = πr^2 - bh/2
A = π(4 cm)^2 - (4 cm)(4 cm)/2
A = 16π cm^2 - 8 cm^2
A = (16π - 8) cm^2
Answer:
27 inches
Step-by-step explanation:
To find the length of the diagonal, we just need to use the cosine relation of the 48° angle.
The adjacent side to the angle is the height of the canvas, and the hypotenuse formed is the diagonal of the canvas. So, we have that:
cos(48) = height / diagonal
0.6691 = 18 / diagonal
diagonal = 18 / 0.6691 = 26.9 inches
Rounding to the nearest inch, the diagonal of the canvas measures 27 inches
Answer:
diameter = m - c
Step-by-step explanation:
In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).
The sum of the lengths of the tangents from points A and B on side "c" is ...
(b-r) +(a-r) = c
(a+b) -2r = c
Now, the problem statement defines the sum of side lengths as ...
a+b = m
and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...
m -d = c
m - c = d . . . . add d-c
The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.
I had a very sweet dog, her name was Lilac. I had her for 13 years and unfortunately she passed away. This shows that no one object is permanent
